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Novosadov [1.4K]
2 years ago
6

Describe the difference between a strong acid and a weak acid?

Chemistry
2 answers:
vesna_86 [32]2 years ago
8 0
A strong acid dissociates completely when you put it in water. So for example, if you put a certain amount of HCl in water, all of it will dissociate into H+ and Cl-A weak acid doesn't undergo full dissociation. So if you put a certain amount of something like CH3COOH (acetic acid) in water, only some of the acetic acid will dissociate into H+ and CH3COO-
zavuch27 [327]2 years ago
6 0
Strong acids have a higher PH while weaker acids have a lower PH

I'm other words, acidic bases have a higher PH whilst less acidic bases have lower PH
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What is the independent variable?<br> (For science)
DiKsa [7]

Answer:

The independent variable is what you change in the experiment.

Explanation:

The independent determines the dependent variable.

6 0
3 years ago
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride. A reaction mixture at 298.15k initially c
uranmaximum [27]

Step 1 : Write balanced chemical equation

The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.

I_{2}  (g) + Cl_{2}  (g) ----->  2 ICl (g)

Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

- The initial concentration of product is assumed as 0

- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products

- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

K_{eq} = \frac{[ICl]^{2}}{[I_{2}][Cl_{2}]}

Step 4 : Solving for x

Keq at 298.15 K is given as 81.9

Let us plug in the equilibrium values (E) for I₂, Cl₂ and ICl from ICE table

81.9 = \frac{(2x)^{2}}{(0.437-x) (0.269-x)}

81.9 = \frac{(2x)^{2}}{x^{2} -0.706x + 0.118}

(2x)^{2} = 81.9 [ x^{2} -0.706x + 0.118]

4x^{2} = 81.9x^{2} -57.8x +9.66

77.9x^{2} -57.8x+9.66 = 0

Solving the above equation using quadratic formula we get

x = 0.488 or x = 0.254

The value 0.488 cannot be used because the change (C) cannot be greater that initial concentration of the reactants.

Therefore the change in concentration of the gases during the reaction is 0.254 M

Hence, x = 0.254 M

From the ICE table, we know that the equilibrium concentration of ICl is 2x

[ICl]_{eq} = 2 ( 0.254) = 0.508 M

The concentration of ICl when the reaction reaches equilibrium is 0.508 M

6 0
3 years ago
A sample of a compound is analyzed and found to contain 0.420 g nitrogen, 0.480g oxygen, 0.540 g carbon and 0.135 g hydrogen. Wh
RSB [31]

Answer:

C2H5NO

Explanation:

constituent elements                    N              O               C                H

Mass composition                     0.420        0.480         0.540         0.135

mole ratio                                   0.42/14       0.48/16      0.54/12         0.135/1

                                              = 0.03                0.03             0.045         0.135

dividing by the smallest           0.03/0.03     0.03/0.03    0.045/0.03 0.135/0.03

ratio                                      =        1                      1                1.5                 4.5

                                             =        1                      1                  2                   5

EMPERICAL FORMULA = C2H5NO

7 0
2 years ago
How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M?
satela [25.4K]
3.5 M has 3.5 moles per litre
so we have one litre, so we need 3.5 moles
moles = mass/molarmass
3.5 * 23 = 80.5
5 0
3 years ago
Read 2 more answers
A sample of oxygen gas has a volume of 150.0 ml when its pressure is .947 atm. what will the volume of the gas be if the tempera
joja [24]
D
Hope it helped you get an A, Kayla.
7 0
3 years ago
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