1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna11 [10]
3 years ago
8

Which of the following would have the slowest rate of diffusion at a given temperature

Chemistry
2 answers:
bonufazy [111]3 years ago
5 0

Answer:

the answer would be Cl2.

Explanation:

MrMuchimi3 years ago
3 0

Chlorine will have the slowest rate of diffusion because it has the highest   relative molecular mass of 71 followed by O₂ with 32, then Neon 20 then He with 2

The rate of diffusion of a gas is inversely proportional to the square root of its relative molecular mass.  

You might be interested in
From goal line to goal line, a football field is 300 ft long. If a player catches the ball while standing on one goal line, runs
KATRIN_1 [288]

Answer:

The player ran 91.44m.

Explanation:

The problem gives you the total distance between goal line to goal line in feet, and the answer must be given in meters, so you should convert the distance the player run from ft to m, because the player run the same distance from goal line to goal line to scores the touchdown.

So, you should apply the following conversion factor:

300ft*\frac{0.3048m}{1ft}= 91.44m

The player ran 91.44m.

3 0
3 years ago
I’ll give the brainliest to whoever gets it right!!!
kramer

Answer:

itll slowly decay

Explanation:

i hope this helps

8 0
3 years ago
The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat
Darya [45]

Answer:

Heat of fusion

Explanation:

The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat of fusion.

The formula for the heat of fusion is given by :

\Delta H=n\Delta H_{fus}

Where

n is no of moles

\Delta H_{fus} is molar heat of the substance

Hence, the correct answer is heat of fusion

8 0
3 years ago
The mass of 2.50 moles of calcium fluoride is ____ grams
Vesna [10]

Answer:

195.187016

Explanation:

3 0
3 years ago
Read 2 more answers
The gas-phase reaction follows an elementary rate law and is to be carried out first in a PFR and then in a separate experiment
astraxan [27]

Answer:

The activation energy is =8.1\,kcal\,mol^{-1}

Explanation:

The gas phase reaction is as follows.

A \rightarrow B+C

The rate law of the reaction is as follows.

-r_{A}=kC_{A}

The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" = 10dm^{3}

Temperature "T" = 300 K

Volumetric flow rate of the reaction v_{o}=5dm^{3}s

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

V= \frac{v_{0}}{k}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]

Rearrange the formula is as follows.

k= \frac{v_{0}}{V}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]............(1)

The feed has Pure A, mole fraction of A in feed y_{A_{o}} is 1.

\epsilon =y_{A_{o}}\delta

\delta = change in total number of moles per mole of A reacte.

=1(2-1)=1

Substitute the all given values in equation (1)

k=\frac{5m^{3}/s}{10dm^{3}}[(1+1)ln \frac{1}{1-0.8}-1 \times 0.8] = 1.2s^{-1}

Therefore, the rate constant in case of the plug flow reacor at 300K is1.2s^{-1}

The rate constant in case of the CSTR can be calculated by using the formula.

\frac{V}{v_{0}}= \frac{X(1+\epsilon X)}{k(1-X)}.............(2)

The feed has 50% A and 50%  inerts.

Hence, the mole fraction of A in feed y_{A_{o}} is 0.5

\epsilon =y_{A_{o}}\delta

\delta = change in total number of moles per mole of A reacted.

=0.5(2-1)=0.5

Substitute the all values in formula (2)

\frac{10dm^{3}}{5dm^{3}}=\frac{0.8(1+0.5(0.8))}{k(1-0.8)}=2.8s^{-1}

Therefore, the rate constant in case of CSTR comes out to be 2.8s^{-1}

The activation energy of the reaction can be calculated by using formula

k(T_{2})=k(T_{1})exp[\frac{E}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})]

In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

E= R \times(\frac{T_{1}T_{2}}{T_{1}-T_{2}})ln\frac{k(T_{2})}{k(T_{1})}

Substitute the all values.

=1.987cal/molK(\frac{300K \times320K}{320K \times300K})ln \frac{2.8}{1.2}=8.081 \times10^{3}cal\,mol^{-1}

=8.1\,kcal\,mol^{-1}

Therefore, the activation energy is =8.1\,kcal\,mol^{-1}

8 0
3 years ago
Other questions:
  • If enough experimental data supports a hypothesis, then it:
    13·2 answers
  • How many moles of solute are contained in a 250.0<br>ml solution with a concentration of 2.5m
    11·1 answer
  • Round the nearseat whole number how many neutrons on average are in atom of osmium?
    7·1 answer
  • In what type of solvation does water surround ionic crystals and pull them apart into ions?
    15·1 answer
  • Flammability is a material’s ability to burn in the presence of
    6·1 answer
  • A frog is an amphibian because they can. Live both in land and water.what is that observation or inference
    10·1 answer
  • Which of these household items is powered by alternating current?
    6·1 answer
  • Define saturated and unsaturated fats​
    9·1 answer
  • Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula
    7·1 answer
  • In a decomposition reaction involving a gaseous product, what must be done for the reaction to reach equilibrium?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!