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IceJOKER [234]
3 years ago
15

You are a high school track & field coach and you have a young female athlete who is running a competitive mile pace (5:20).

This would make her competitive at the state and national level. You want to help this athlete to maintain and even increase her competitive potential. What would you do?
Chemistry
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

By ensuring she is giving speed endurance training

Explanation:

Speed endurance training would be the most ideal in helping an athlete to maintain and even increase her competitive potential.

The speed endurance training would help the athlete maintain and attain a high speed for a longer duration of time.

This would make the athlete get used to running an improved time for much longer distances.

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A chemical equation is shown below. KNO3 → KNO2 + O2 What are the coefficients that should be added to balance this equation? Us
uysha [10]

20) Balanced chemical equation: 2KNO₃ → 2KNO₂ + O₂.

Potassium nitrate is decomposed on potassium nitrite and oxygen.

According to principle of mass conservation, number of atoms must be equal on both side of chemical reaction.  

There are two potassium atoms, two nitrogen atoms and six oxygen atoms on both side of balanced chemical reaction.  

Decomposition is reaction where one substance (in this example potassium nitrate) is broken down into two or more simpler substances (potassium nitrite and oxygen).  

21) The answer is:

Balanced chemical reaction: double recplacement reaction.

MgCl₂(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2NaCl(aq).

The magnesium (Mg) and the sodium (Na) replace each other making this a double replacement reaction.

Reactivity series is an empirical progression of a series of metals, arranged by their reactivity from highest to lowest (alkaline metals have highest reactivity and Noble metals lowest reactivity):  

K > Ba > Sr > Na > Ca > Mg > Be > Al > Mn > Zn > Cr> Fe > Cd > Co > Ni > Sn > Pb > H(in acids) > Cu > Hg > Ag.

Metal higher in the reactivity series will displace another and it will be oxidized.

Magnesium is higher it this series than aluminium and aluminium is higher than copper.

22) The answer is: half life is 22 years.

Half-life is the time required for a quantity (in this example mass of the element) to reduce to half its initial value and is independent of initial concentration.

Mass of the element is reduced by half in 22 years from 45 grams to 22.5 grams.

First calculate the radioactive decay rate constant λ:

λ = 0.693 ÷ t.

λ  = 0.693 ÷ 22 y.

λ = 0.0315 1/y.

ln(m/m₀) = -λ·t₁.

ln(4.8125/308) = -0.0315 1/y · t₁.

t₁ = 132.02 y.

7 0
3 years ago
Which statement best explains the formation and distribution of oil?
liraira [26]
What are the statements?
7 0
3 years ago
A person's heartbeat is 66 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th
BartSMP [9]
<span>88(60) 24(365) that should be the answer after you figure it out.</span>
5 0
3 years ago
Ok! Water is added to 200. ml of a 2.0 M solution of CaCI2 to increase the volume of the solution to 450. ml. So what is the new
dexar [7]

Answer:

0.89M

Explanation:

Because moles of solute do not change, we can write

M1V1 = M2V2

M - molarity, V - volume of solution

2.0M*200mL = M2*450mL

M2 = 0.89 M

7 0
4 years ago
Determine the bond order from the molecular electron configurations. ( σ 1 s ) 2 ( σ 1 s * ) 2 ( σ 2 s ) 2 ( σ 2 s * ) 2 ( σ 2 p
almond37 [142]

Explanation:

The bond order is defined as number of electron pairs present in a bond of the two atoms.

The formula of bond order is given by:

= \frac{1}{2}\times (\text{Number of bonding electrons}-\text{Number of anti-bonding electrons})

1)  (\sigma 1 s )^2 ( \sigma 1 s*)^2 (\sigma 2s )^2 ( \sigma 2 s*)^2 ( \sigma 2 p )^2 ( \pi2 p )^4 (\pi 2 p *)^2

Number of bonding electrons = 10

Number of anti-bonding electrons = 6

The bond order : \frac{1}{2}\times (10-6)=2

2) ( \sigma 1 s )^2 ( \sigma 1 s * )^2 ( \sigma 2 s )^2

Number of bonding electrons = 4

Number of anti-bonding electrons = 2

The bond order : \frac{1}{2}\times (4-2)=1

8 0
3 years ago
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