The empirical and molecular formula would be
and
respectively.
<h3>Empirical formula</h3>
The compound contains N and O.
N O
0.608/14 = 0.0434 1.388/16 = 0.0867
Divide by the smallest.
N = 1 O = 2
Thus, the empirical formula would be 
To get the molecular formula:
Empirical formula mass = 14 + (16x2) = 46
n = molar mass/empirical formula mass
= 92/46 = 2
Thus, the molecular formula would be 
More on empirical formulas can be found here: brainly.com/question/14044066
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1 ounces ----------- 29.5735 mL
5 ounces ----------- ??
5 x 29.5735 / 1 => 147.868 mL
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The approximate size of solute particles in a solution is 1 nanometer.
Explanation:
Solute and solvent are the two components required to prepare a solution. Solute is the one which is dissolved in the solvent to prepare a solution. So solute should be of lesser concentration compared to the solvent. Also the particle size of solute should be lesser in size compared to the solvent for easy diffusion and substitution. Mostly it is seen that if the solute is finer and having a size of less than 1 nanometer can be easily dissolved in the solvent.
So for forming homogeneous solutions, the solute is considered to be of materials having the particle size of 1 nanometer for perfect dissolving.
Thus, the approximate size of solute particles in solution is 1 nanometer.
Answer by YourHope:
Hi! :)
Answers:
A catalyst is a substance that changes the rate of the reaction, and is not consumed in the reaction!
A solution is a uniform mixture of molecules or ions of one substance in another!
A solute is the substance dissolved in a solution!
A solution is the substance that does the dissolving in a solution!
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Answer:
Atomic mass of N relative to H is 13.9.
In periodic table mass of N is around 14 RAM
Explanation:
1 mol of ammonia has 1 mol of N, and 3 mole of H
NH₃
1 mol of H weighs 1 g, so the mole of H, present in ammonia are:
1.712 g / 1 g/m = 1.712 mole
Since the ratio is 1:3
1.712 mole/3 = 0.57 mole of N are present in the amonia
To calculate the atomic mass of N relative to H, let's consider it as molar weight.
Molar weight = mass / mole
7.933 g / 0.57 mole = 13.9 g/m