An object travels in a straight line, then comes to rest
Answer:
k = 39.2 N / m
Explanation:
The 200 g block is accelerated by the force of friction between the blocks. Let's use Newton's second law
N- W = 0
N = W
fr = ma
μ N = ma
μ mg = ma
a=μ g
Let's look for the acceleration of the largest block that has oscillatory movement
x = A cos (w t)
A = 0.05 m
The maximum acceleration is cos wt = ±1
a = A w2
a = A k / m
We substitute and calculate
μ g = A k / M
k = μ g M / A
The mass that performs the oscillation is the mass of the two bodies
M = m1 + m2
k = 0.2 9.8 (0.800+ 0.200) /0.05
k = 39.2 N / m
Answer:
Velocity is 3.02 m/s at an angle of 53.13° below X-axis.
Explanation:
Let unknown velocity be v.
Here momentum is conserved.
Initial momentum = Final momentum
Initial momentum = m x 6i + m x 0i = 6m i
Final momentum = m x (4.8cos 30 i + 4.8sin 30 j) + m x v = 4.16 m i + 2.4 m j + m v
Comparing
4.16 m i + 2.4 m j + m v = 6m i
v = 1.84 i - 2.4 j
Magnitude of velocity
Direction,
Velocity is 3.02 m/s at an angle of 53.13° below X-axis.
Answer:
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