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NARA [144]
3 years ago
9

A 25 kg box on a horizontal frictionless surface is moving to the right at a speed of 5.0 m s. The box hits and remains attached

to one end of a spring of negligible mass whose other end is attached to a wall. As a result, the spring compresses a maximum distance of 0.60 m. (a) i. The spring does work on the box from the moment the box first hits the spring to the moment the spring first reaches its maximum compression. Indicate whether the work done by the spring is positive, negative, or zero.
Physics
1 answer:
seropon [69]3 years ago
6 0

Answer:

Explanation:

Work done by the spring is negative .

Work done by force F creating displacement  d is given by the following expression .

Work = F x d

Both force and displacement are vector quantity .

When direction of force and direction of displacement is same , work is positive . When direction of force and direction of displacement is opposite , work is negative .

When spring is compressed , it exerts a restoring or opposing force in a direction opposite to the direction of displacement of box . Hence here force is opposite to displacement . Restoring force acts opposite to displacement . Hence work done by spring on box is negative .

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A horizontal force, F, acts on a crate weighing 8 N, which moves on a horizontal floor at constant speed. The coefficient of fri
RoseWind [281]

The answer is 24 J

F K =.25*8 N

     = 2N

F = f k = 2 N

Since a = 0

W = f * s

 2 N * 12 m = 24 J

The coefficient of friction is a ratio used to quantify the friction force among two gadgets when it comes to the everyday pressure this is keeping them collectively. The coefficient of friction is critical attention at some stage in material selection and floor requirement determination.

For instance, ice on steel has a low coefficient of friction – the 2 materials slide past each different without problems – whilst rubber on the pavement has an excessive coefficient of friction – the substances no longer slide past each other without difficulty.

The coefficient of friction is dimensionless and it does not have any unit. it is a scalar, meaning the direction of the force does not have an effect on the physical quantity. The coefficient of friction depends on the gadgets that are causing friction.

Learn more about the coefficient of friction here brainly.com/question/20241845

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7 0
2 years ago
A wheel of mass 60.0 kg is pushed with a net force of 26.4 N. Find acceleration.
worty [1.4K]

F= ma; a= F/m

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4 0
3 years ago
If the net force acting on a stationary object is zero then the object will
Drupady [299]
If the net force is zero, then there is no acceleration, which means no change in velocity. The velocity starts at zero, so it must remain at zero. Therefore, the object will not move.
7 0
3 years ago
The rate constant of a chemical reaction increased from 0.100 s−1 to 3.10 s−1 upon raising the temperature from 25.0 ∘C to 51.0
forsale [732]

Answer:

A. (1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹

B. ln (k₁/k₂) = -3.434

C. E = 106.13 KJ/mol

Explanation:

Part A:

we have:

T₁ = 25°C = 298 K

T₂ = 51°C = 324 K

(1/T₂ - 1/T₁) = (1/324 k - 1/298 k)

<u>(1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹</u>

<u></u>

Part B:

ln (k₁/k₂) = ln (0.1/3.1)

<u>ln (k₁/k₂) = -3.434</u>

Part C:

The activation energy can be found out by using Arrhenius Equation:

ln (k₁/k₂) = E/R  (1/T₂ - 1/T₁)

where,

E = Activation Energy

R = General Gas Constant = 8.314 J/mol.k

Therefore,

-3.434 = (E/8.314 J/mol.k)(-2.69 x 10⁻⁴ K⁻¹)

<u>E = 106134.8 J/mol = 106.13 KJ/mol</u>

8 0
3 years ago
Question 5
Alekssandra [29.7K]

Answer:

Question 5: The outer core has a lower temperature and lower pressure than the inner core

This is because the outer core is not as hot as the inner core. It is also under slightly less pressure. Due to this, the outer core is liquid and less dense than the inner core.

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5 0
3 years ago
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