Moving material along certain gradients is necessary for osmosis, diffusion, filtration, and the transport of ions away from similar charges.
Osmosis is the flow of solvent molecules over a semi-permeable membrane from an area of lower concentration to a region of higher concentration Molecules diffuse when they travel from one area of higher concentration to another area of lower concentration The process of filtering involves moving liquid substances through a separating material known as a filter in order to separate solid particles from liquid. Due to the difference in pressures between the solid and liquid substances, this process is made feasible. Because of the difference in electrical potentials between the charges, ions move away from like charges.
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Answer: A solution is made by dissolving 27.8 g of nicotine (Molar Mass = 160 g/mol) in 145 g of cyclohexane (C6H12) to form 142 mL of solution. Calculate the mole fraction of the solute and the molarity, respectively, of this solution.
Explanation:
Answer:
- Britta paid more per kilometer driven
Explanation:
<u>1) Britta:</u>
- Distance traveled: 1,250 Km
- Gasoline price: 1.23 euros / liter
Cost per km = total cost of gasoline / distance traveled
Cost per km = gasoline used × gasoline price / distance traveled
Cost per km = 209 liter × 1.14 (euro / liter) / 1,250 km = 0.19 euro / km
<u>2) Pierce:</u>
- Distance traveled: 1,405 km
- Gasoline price = 1.23 euros / liter
Cost per km = 175 liter × 1.23 (euro / liter) / 1,405 km = 0.15 euro / km
<u>3) Comparison:</u>
- 0.19 > 0.15 ⇒ Britta paid more per kilometer driven
Answer:
The ionization of 0.250 moles of H₂SO₄ will produce 0.5 moles of H⁺ (hydrogen ion)
Explanation:
From the ionization of H₂SO₄, we have
H₂SO₄ → 2H⁺ + SO₄²⁻
Hence, at 100% yield, one mole of H₂SO₄ produces two moles of H⁺ (hydrogen ion) and one mole of SO₄²⁻ (sulphate ion), therefore, 0.250 moles of H₂SO₄ will produce 2×0.250 moles of H⁺ (hydrogen ion) or 0.5 moles of H⁺ (hydrogen ion) and 0.25 moles of SO₄²⁻ (sulphate ion).
That is; 0.250·H₂SO₄ → 0.5·H⁺ + 0.250·SO₄²⁻.
