I don’t have a picture but I can describe it to you.
The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.
The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.
Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.
Hope this helps!
<span>Mass of CH2 = 12 + 2 = 14 g/mol
The number of CH2s there are.
So since the total mass is 84.2 g/mol.
The solution is
84.2/14 = 6.012 thus the answer is 6
There are 6(CH2)
So the molecular formula is C6H12</span>