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3 years ago

The oceans are the major source of moisture for the water cycle. What goes in the blank?

Chemistry

2 answers:

erma4kov [3.2K]3 years ago

8 0

Please attach a diagram with the blank.

Alexus [3.1K]3 years ago

7 0

Can you write more bout this??!

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Can somobody help me??????

Katen [24]

Answer:

Interphase, mitosis, and cytokenesis

Explanation:

Interphase is the phase in which the cell is growing, and mitosis and cytokenesis make up the phase in which daughter cells are formed

5 0

2 years ago

What do i need to do

Rufina [12.5K]

Answer:

2. C population

3. C population

4. A community

5. B ecosystem

6. B how organisms interact

Explanation:

Yes, both 2 and 3 have the same answer. Im very sure that the correct answer.

7 0

3 years ago

Read 2 more answers

Aluminum–lithium (Al–Li) alloys have been developed by the aircraft industry to reduce the weight and improve the performance of

brilliants [131]

Answer:

6.54% is the required concentration of lithium in an alloy (Al–Li).

Explanation:

Suppose 100 grams of an alloy of aluminium and lithium.

Density of an alloy = d $2.14 g/cm^3$

Volume of an alloy = V

$V=\frac{100 g}{2.14 g/cm^3}=46.73 cm^3$

Volume of aluminum = $v_1$

Mass of aluminum = x

Density of aluminum = $d_1=2.71 g/cm^3$

$v_1=\frac{x}{d_1}$

Volume of lithium = $v_2$

Mass of lithium = y

Density of lithium= $d_2=0.534 g/cm^3$

$v_2=\frac{y}{d_2}$

$x+y=100$ ..[1]

$v_1+v_2=V$

$\frac{x}{d_1}+\frac{y}{d_2}=46.73 cm^3$

$\frac{x}{2.71}+\frac{y}{0.534}=46.73$ ..[2]

Solving [1] and [2] :

we get :

x = 93.46 g

y = 6.54 g

Concentration of Li (in wt%) that is required:

$Li\%=\frac{6.54 g}{100 g}\times 100=6.54\%$

5 0

3 years ago

1. Which population of organisms depends on eating another population of organisms for

Aloiza [94]

Answer:

predation

Explanation:

Predation An interaction in which one organism kills another for food. Prey An organism that is killed and eaten by another organism.

8 0

2 years ago

When the nuclide iron-59 undergoes beta decay: The name of the product nuclide is . The symbol for the product nuclide is .

Travka [436]

Answer:

Explanation:

⁵⁹₂₆Fe --------- ⁰₋₁e + ⁵⁹₂₇Co

Co- 59 is known as Cobalt

its symbol is ⁵⁹₂₇Co

5 0

3 years ago