Nguyên tử của nguyên tố X ở chu kỳ 3 có tỉ lệ electron trên phân lớp s và p là 6/11. Nguyên tố Y ở chu kỳ 4 nhóm A có tỉ lệ elec
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1. No. 108 g of Ag has a lower number of atoms than 80 g of Ca.
2. The gram of in 3 moles of the compound would be 240 g.
3. 1.20 x atoms
4. The grams of hydrogen in 3.6 x molecules of
would be 18 grams.
According to Avogadro, 1 mole of a substance contains 6.022 x molecules or atoms.
Recall that: mole = mass/molar mass
1. 108 g of Ag would be equivalent to: 108/108 = 1 mol.
80 g of Ca would be equivalent to: 80/40 = 2 mol
Since 1 mol is equivalent to 6.022 x molecules or atoms, it means 80 g of Ca has twice as atoms as 108 g of Ag.
2. 3 mol sample of would be equivalent to: 3 x 80 = 240 g
3. 124 g of would be equivalent to: 124/62 = 2 mol
Number of atoms = 2 x 6.022 x
= 1.20 x atoms
4. 3.6 x molecules of
would be equivalent to:
3.6 x /6.022 x
= 6 mol of
From the above equation, 1 mole of produces 3 moles of hydrogen. Thus, 6 moles of
would be equivalent to 18 moles of hydrogen.
18 moles of hydrogen = 18 x 1
= 18 g
More on the number of atoms in samples can be found here: brainly.com/question/28834341
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