All categories

4 years ago

2.5 h = [?] minutes.

Mathematics

1 answer:

Gnom [1K]4 years ago

7 0

150 minutes
1 h=60
60×2=120
.5 h=30
120+30=150

You might be interested in

Which system of equations is graphed below

pychu [463]

Hello. I could help you with this question because i'm actually learning that too. Just create another question showing the entire graph so that I could help you.

7 0

3 years ago

I need help with the first part I will give brainliest

kaheart [24]

Answer:15 candy bars are solddd

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t

rosijanka [135]

Answer:

$Height = 12cm$

$Radius = 6cm$

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

$V = 432\pi$

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

$V = \pi r^2h\\$

Substitute 432π for V

$432\pi = \pi r^2h$

Divide through by π

$432 = r^2h$

Make h the subject:

$h = \frac{432}{r^2}$

Surface Area (A) of a cylinder is calculated as thus:

$A=2\pi rh+2\pi r^2$

Substitute $\frac{432}{r^2}$ for h in $A=2\pi rh+2\pi r^2$

$A=2\pi r(\frac{432}{r^2})+2\pi r^2$

$A=2\pi (\frac{432}{r})+2\pi r^2$

Factorize:

$A=2\pi (\frac{432}{r} + r^2)$

To minimize, we have to differentiate both sides and set $A' = 0$

$A'=2\pi (-\frac{432}{r^2} + 2r)$

Set $A' = 0$

$0=2\pi (-\frac{432}{r^2} + 2r)$

Divide through by $2\pi$

$0= -\frac{432}{r^2} + 2r$

$\frac{432}{r^2} = 2r$

Cross Multiply

$2r * r^2 = 432$

$2r^3 = 432$

Divide through by 2

$r^3 = 216$

Take cube roots of both sides

$r = \sqrt[3]{216}$

$r = 6$

Recall that:

$h = \frac{432}{r^2}$

$h = \frac{432}{6^2}$

$h = \frac{432}{36}$

$h = 12$

Hence, the dimension that requires the least amount of material is when

$Height = 12cm$

$Radius = 6cm$

3 0

3 years ago

Select the best answer for the question.

fgiga [73]

The answer is D - 4/5

7 0

3 years ago

Read 2 more answers

Solve the systems using substitution.<br> 1.6x + 2y = -2<br> 4x + y = 1

Schach [20]

$\begin{array}{ccc}(1)\\(2)\end{array}\ \left\{\begin{array}{ccc}6x+2y=-2\\4x+y=1\end{array}\right\\\\4x+y=1\ \ \ |subtract\ 4x\ from\ both\ sides\\y=1-4x\\\\subtitute\ y=1-4x\ to\ (1):\\\\6x+2(1-4x)=-2\\6x+2\cdot1+2\cdot(-4x)=-2\\6x+2-8x=-2\\-2x+2=-2\ \ \ \ |subtract\ 2\ from\ both\ sides\\-2x=-4\ \ \ |divide\ both\ sides\ by\ (-2)\\\boxed{x=2}\\\\subtitute\ the\ value\ of\ x\ to\ the\ y=1-4x:\\\\y=1-4\cdot2\\y=1-8\\\boxed{y=-7}\\\\Answer: \left\{\begin{array}{ccc}x=2\\y=-7\end{array}\right$

6 0

3 years ago