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3 years ago

Assume a random variable x is normally distributed with mean = 90 and standard deviation = 5. Find the indicated probability.

Mathematics

1 answer:

nikklg [1K]3 years ago

7 0

Answer:

16%

Step-by-step explanation:

The indicated probability is actually the area under the standard normal curve to the left of the mean. I used the function normalcdf( on my TI-83 Plus calculator to find this quantity:

normalcdf(-1000,85,90,5) = 0.1587.

Note #1: This quantity (area / probability) is the area to the left of 85.

Note #2: by the Empirical Rule, 68% of data lies within 1 s. d. of the mean, so the area between the mean (90) and the score (85) is half of 68%, or 34%. Subtracting this from 50% (the area to the left of the mean), we get 16%, which is roughly equivalent to the 0.1587 we got earlier.

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NeTakaya

Answer:4

Step-by-step explanation:

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3 years ago

Any volunteer please help

den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

The point = (-2, 11)

m = 4/3

The point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Thus, the equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

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3 years ago

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bezimeni [28]

I DON'T KNOW THE ANSWER BUT THANKS FOR THE POINT$

Step-by-step explanation:

I DON'T KNOW THE ANSWER BUT THANKS FOR THE POINT$

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2 years ago

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3 years ago

Two sides of a right triangle measure 2 units and 4 units.

wel

Answer:

Step-by-step explanation:

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