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Alinara [238K]
4 years ago
7

Explain why you get a basic solution when you dissolve NaF in water.

Chemistry
1 answer:
SashulF [63]4 years ago
5 0

Answer:

<em>That's </em><em>because</em><em> </em><em>in </em><em>water</em><em> </em><em>NaF </em><em>will </em><em>dissolve</em><em> </em><em>to </em><em>produce </em><em>Na</em><em>+</em><em>,</em><em>the </em><em>conjugate </em><em>base </em><em>of </em><em>a </em><em>strong</em><em> </em><em>acid </em><em>which</em><em> </em><em>will </em><em>not </em><em>react </em><em>with </em><em>water.</em><em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em> </em><em>F- </em><em>will </em><em>behave </em><em>like </em><em>a </em><em>bronsted </em><em>base,</em><em> </em><em>and </em><em>accept</em><em> </em><em>a </em><em>proton </em><em>from </em><em>water.</em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>is </em><em>called </em><em>hydrolysis</em><em> </em><em>reaction,</em><em> because</em><em> </em><em>a </em><em>molecule</em><em> </em><em>of </em><em>water </em><em>is </em><em>broken </em><em>up.</em>

<em>a </em><em>conjugate</em><em> base</em><em> </em><em>is </em><em>what </em><em>I </em><em>leftover </em><em>after </em><em>an </em><em>acid </em><em>loses </em><em>a </em><em>hydrogen</em><em> </em><em>ion.</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

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A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm
Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 ^{\circ}C or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55^{\circ}C = 328 K

Initial pressure = P = 845 mmHg

Assuming final  to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg  

The final temperature is obtained by following relation at constant volume

\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}

The final temperature is 407.57 K

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3 years ago
Elements can be represented by chemical symbols. Which of the following is the correct way to write the chemical symbol for sodi
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3 years ago
What is the mass number of an ion with 107 electrons, 157 neutrons, and a 1 charge?
Oksi-84 [34.3K]
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4 0
3 years ago
Place the following substances in order of decreasing vapor pressure at a given temperature: BeF2, CH3OH, OF2?
Anit [1.1K]

Answer:

(b) BeF2 > OF2 > CH3OH

Explanation:

The degree and type of intermolecular forces present in a substance influences its vapour pressure considerably. The greater the magnitude and strength of intermolecular forces in the substance, the lower the vapour pressure of the substance.

BeF2 molecules are held together by weak vanderwaals forces hence BeF2 will exhibit the least degree of intermolecular interaction and have the highest vapour pressure. OF2 molecules are bound together by dipole interactions hence it will exhibit a lower vapour pressure compared to BeF2. CH3OH molecules form hydrogen bonds with water molecules hence it will exhibit the least vapour pressure among the trio.

3 0
3 years ago
Answer each of the following questions with increases, decreases, or does not change.
Kaylis [27]

Answer:

1) Increases

2) decreases

3) increases

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Explanation:

When the intermolecular forces in a liquid increases, the greater vapour pressure of the liquid decreases accordingly.

Since the vapour pressure is proportional to temperature, as temperature increases, the vapour pressure increases alongside.

As intermolecular forces increases, the boiling point increases accordingly since more energy is required to break intermolecular bonds.

Lastly, the greater the surface area, tell greater the vapour pressure since more liquid surface area is now available.

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4 years ago
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