Answer:
C₆H₅COOH Benzoic Acid
Explanation:
Here we are using the extraction method to separate benzoic acid from naphtalene in the ether solution by reacting it with the base sodium bicarbonate to produce the salt sodium benzoate ( naphtalene remains in the organic layer ) .
The sodium benzoate is completely soluble in the aqueous layer being a salt, and reacts with hydrochloric acid ( again an acid base reaction ) which precipitates the benzoic acid since the it is insoluble in water hence separating it.
First of all, it is a nucleic acid, not nuclear acid.
Examples are DNA and RNA( Deoxyribonucleic Acid and Ribonucleic Acid)
POH = - log [ OH-]
pOH = - log [ 1 x 10⁻¹²]
pOH = 12
The balanced equation for the above double displacement reaction is as follows;
2KCl + Pb(NO₃)₂ ---> PbCl₂ + 2KNO₃
Stoichiometry of KCl to PbCl₂ is 2:1
This means that 2 mol of KCl would react with every 1 mol of PbCl₂
The molarity of KCl - 0.596 M
in 1 L of KCl there are 0.596 mol
Therefore in 10.0 mL of KCl there are -
Number of KCl moles reacted - 0.00596 mol
according to stoichiometry
number of PbCl₂ moles formed - 1/2 x number of KCl moles reacted
Therefore number of PbCl₂ moles formed - 0.00596 mol/2 = 0.00298 mol
molar mass of PbCl₂ - 278 g/mol
mass of PbCl₂ formed - 278 g/mol x 0.00298 mol = 0.828 g