At stp conditions (
), the speed of sound is
The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:
where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
The mass of the large truck is determined as 5680 kg.
<h3>Mass of the truck</h3>
The mass of the truck is calculated as follows;
P = mv
where;
- P is momentum
- m is mass
- v is velocity
m = P/v
m = 125000/22
m = 5680 kg
Thus, the mass of the large truck is determined as 5680 kg.
Learn more about momentum here: brainly.com/question/7538238
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<h2>
After 26.28 seconds projectile returns 26.28 seconds.</h2>
Explanation:
Initial velocity = 450 ft/s = 137.16 m/s
Angle, θ = 70°
Consider the vertical motion of projectile,
When the projectile return to the ground we have
Displacement, s = 0 m
Acceleration, a = -9.81 m/s²
Initial velocity, u = 137.16 x sin70 = 128.89 m/s
Substituting in s = ut + 0.5 at²
s = ut + 0.5 at²
0 = 128.89 x t + 0.5 x (-9.81) x t²
t² - 26.28 t = 0
t ( t- 26.28) = 0
t = 0 s or t = 26.28 s
After 26.28 seconds projectile returns 26.28 seconds.
