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3 years ago

How is elastic energy related to mechanical energy?

1 answer:

6 0

Elastic energy is potential energy and mechanical energy is kinetic energy.

Many times, elastic energy is a consequence of mechanical energy. When energy is transferred to an object through mechanical energy, it can often displace or deform the object. This stored energy because of the deformation is called elastic energy.

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A 92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving

Harman [31]

Answer:

13.7m

Explanation:

Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.

After the push

$m_av_a + m_sv_s = 0$

Where $m_a = 92kg$ is the mass of the astronaut, $m_s = 1200kg$ is the mass of the satellite, $v_s = 0.14 m/s$ is the speed of the satellite. We can calculate the speed $v_a$ of the astronaut:

$v_a = \frac{-m_sv_s}{m_a} = \frac{-1200*0.14}{92} = -1.83 m/s$

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

4 0

3 years ago

A student charges a balloon and then brings it near a metal sphere hanging from the

Hunter-Best [27]

Answer:

Explanation:

the balloon has a negative charge and the metal sphere has a positive charge

3 0

3 years ago

Read 2 more answers

Which graph of motion shows the motion of an object in equilibrium?

Dovator [93]

Answer:

The graph line that doesn't change in amounts.

Explanation:

Meaning if its a straight line horizontally across it is in equilibrium. If you don't know what I mean, search up equilibrium graph, and it will show you what I am talking about.

8 0

3 years ago

Consider a uniform sphere, which has a mass of 4.80 kg and a radius of 22.0 cm. A tangential force of 11.2 N is applied to the o

Tcecarenko [31]

Answer:

The moment of inertia of this sphere is $0.0929\ kg-m^2$ .

Explanation:

It is given that,

Mass of the sphere, m = 4.8 kg

Radius of the sphere, r = 22 cm = 0.22 m

Tangential force, F = 11.2 N

The moment of inertia of the uniform sphere is given by :

$I=\dfrac{2}{5}mr^2$

$I=\dfrac{2}{5}\times 4.8\ kg\times (0.22\ m)^2$

$I=0.0929\ kg-m^2$

So, the moment of inertia of this sphere is $0.0929\ kg-m^2$ . Hence, this is the required solution.

8 0

3 years ago

Two simple pendulums are in two different places. The length of the second pendulum is 0.4 times the length of the first pendulu

faltersainse [42]

Answer:

$\sqrt{\frac{4}{9}}$

Explanation:

The frequency of a simple pendulum is given by:

$f=\frac{1}{2\pi}\sqrt{\frac{g}{L}}$

where

g is the acceleration of gravity

L is the length of the pendulum

Calling $L_1$ the length of the first pendulum and $g_1$ the acceleration of gravity at the location of the first pendulum, the frequency of the first pendulum is

$f_1=\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}$

The length of the second pendulum is 0.4 times the length of the first pendulum, so

$L_2 = 0.4 L_1$

while the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum, so

$g_2 = 0.9 g_1$

So the frequency of the second pendulum is

$f_2=\frac{1}{2\pi}\sqrt{\frac{g_2}{L_2}}=\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}$

Therefore the ratio between the two frequencies is

$\frac{f_1}{f_2}=\frac{\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}}{\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}}=\sqrt{\frac{0.4}{0.9}}=\sqrt{\frac{4}{9}}$

8 0

3 years ago