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Delicious77 [7]
3 years ago
5

How is elastic energy related to mechanical energy?

Physics
1 answer:
djyliett [7]3 years ago
6 0
Elastic energy is potential energy and mechanical energy is kinetic energy.

Many times, elastic energy is a consequence of mechanical energy. When energy is transferred to an object through mechanical energy, it can often displace or deform the object. This stored energy because of the deformation is called elastic energy.
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A ball of mass 0.120 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.600 m. W
Karo-lina-s [1.5K]
Before we find impulse, we need to find the initial and final momentum of the ball.

To find the momentum of the ball before it hit the floor, we need to figure out its final velocity using kinematics.

Values we know:
acceleration(a) - 9.81m/s^2 [down]
initial velocity(vi) - 0m/s
distance(d) - 1.25m [down]

This equation can be used to find final velocity:

Vf^2 = Vi^2 + 2ad

Vf^2 = (0)^2 + (2)(-9.81)(-1.25)

Vf^2 = 24.525

Vf = 4.95m/s [down]

Now we need to find the velocity the ball leaves the floor at using the same kinematics concept.

What we know:
a = 9.81m/s^2 [down]
d = 0.600m [up]
vf = 0m/s

Vf^2 = Vi^2 + 2ad

0^2 = Vi^2 + 2(-9.81)(0.6)

0 = Vi^2 + -11.772

Vi^2 = 11.772

Vi = 3.43m/s [up]

Now to find impulse given to the ball by the floor we find the change in momentum.

Impulse = Momentum final - momentum initial

Impulse = (0.120)(3.43) - (0.120)(-4.95)

Impulse = 1.01kgm/s [up]
8 0
3 years ago
Read 2 more answers
A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) I=0.0085\ A

Explanation:

Given:

  • radius if the coil, r=0.0395\ m
  • no. of turns in the coil, n=520
  • variation of the magnetic field in the coil, B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4
  • resistor connected to the coil, R=560\ \Omega

(a)

we know, according to Faraday's Law:

emf=n.\frac{d\phi}{dt}

where:

d \phi= change in associated magnetic flux

\phi= B.A

where:

A= area enclosed by the coil

Here

A=\pi.r^2

A=\pi\times 0.0395^2

A=0.0049\ m^2

\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049

So, emf:

emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]

emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]

emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]

emf= 0.0306+3.516\times 10^{-4}\ t^3

(b)

Given:

t_0=5.25\ s

Now, emf at given time:

emf=4.7755\times 10^{-2}\ V

∴Current

I=\frac{emf}{R}

I=\frac{4.7755\times 10^{-2}}{560}

I=8.5\times 10^{-5} A

6 0
4 years ago
What is another name for the range of motion in your joint
Neporo4naja [7]

Answer:Gliding

Explanation:

Because it’s an ball and socket joint

3 0
3 years ago
What is the acceleration of a car initially traveling at -5m/s and<br> reaching -22m/s in 3s.
lozanna [386]

Answer:

a=-5.67\ m/s^2

Explanation:

Given that,

Initial velocity, u = -5 m/s

Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2

So, the acceleration of the car is -5.67\ m/s^2.

4 0
3 years ago
Define specific vision??​
iren2701 [21]

Answer:an inspirational statement of an idealistic emotional future

Explanation:

I don't know if it's right tho

5 0
3 years ago
Read 2 more answers
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