Answer:
v= 4055.08m/s
Explanation:
This is a problem that must be addressed through the laws of classical mechanics that concern Potential Gravitational Energy.
We know for definition that,
We must find the highest point and the lowest point to identify the change in energy, so
Point a)
The problem tells us that an object is dropped at a distance of h = 1.15134R over the earth.
That is to say that the energy of that object is equal to,
Point B )
We now use the average radius distance from the earth.
Then,
By the law of conservation of energy we know that,
clearing v,
Therefore the speed of the object when it strikes the Earth’s surface is 4055.08m/s
<span>Object B stays neutral but becomes polarized.
Hope this helps.
~Jurgen</span>
<span>The relationship between two quantities that increase or decrease together is called directly proportional.
It is a directly proportional relationship because being directly proportional means that if one increases so does the other, and if one goes down so does the other.</span>
the attraction is maximum between b and c. while the force between a and d is minimum
Answer:
0.26315 s
Explanation:
The frequency of the ball tied to a string system is 3.8 rev/s.
That means in one second the ball will complete 3.8 revolutions.
The time period will be the reciprocal of this frequency
The time period is 0.26315 s
It can be also solved in the following way
The time period is 0.26315 s
