Answer: it might be the 2 one but i am not sure
Step-by-step explanation:
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
There's no way to know this without knowing the number of pencils he started with
Answer:
The greatest number of the books that could have been borrowed during the week is 36
Step-by-step explanation:
Let's create an equation which represent this problem, where will rest the book borrow and add the book returned to the 40 initial amount of book on Monday, to get the 22 book in the shelf on Saturday morning
40 (book on the shelf on Monday) - x (book borrowed) + 0.5 * x (50 % of the book was returned before Saturday) = 22 (books in the shelf on Saturday morning)
40 - x + 0.5 * x = 22
40 - 0.5*x = 22
18 = 0.5 * x
18/0.5 = x
36 = x
The amount of borrowed books is 36
Answer:
$3 per candy bar
Step-by-step explanation:
:))