Which expression has a positive value?
1 answer:
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As I read this one, is just a decay exponential equation... so
A = P(1 + r)ᵗ where "t" is days passed. . hmm in this case is decay, so negative rate A = P(1 - r)ᵗ, and the decimal amount would be 0.00877 for the rate
62% of P, the original value, is just 0.62P, now... if we hmm take P as just 1, it could be any amount, but 62% of 1,000,000 is just 62% of 1 times 1,000,000
so, for the sake of comparing it with a percentage, 1 will do
![\bf 0.62P=P(1-0.00877)^t\implies P=1\implies 0.62=(1-0.00877)^t \\\\\\ ln(0.62)=ln[(1-0.00877)^t]\implies ln(0.62)=t\cdot ln(1-0.00877) \\\\\\ \cfrac{ln(0.62)}{ln(0.99123)}=t](https://tex.z-dn.net/?f=%5Cbf%200.62P%3DP%281-0.00877%29%5Et%5Cimplies%20P%3D1%5Cimplies%200.62%3D%281-0.00877%29%5Et%0A%5C%5C%5C%5C%5C%5C%0Aln%280.62%29%3Dln%5B%281-0.00877%29%5Et%5D%5Cimplies%20ln%280.62%29%3Dt%5Ccdot%20%20ln%281-0.00877%29%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bln%280.62%29%7D%7Bln%280.99123%29%7D%3Dt)
A = P(1 + r)ᵗ where "t" is days passed. . hmm in this case is decay, so negative rate A = P(1 - r)ᵗ, and the decimal amount would be 0.00877 for the rate
62% of P, the original value, is just 0.62P, now... if we hmm take P as just 1, it could be any amount, but 62% of 1,000,000 is just 62% of 1 times 1,000,000
so, for the sake of comparing it with a percentage, 1 will do
Answer:
She will earn $85 in 10 hours.
Step-by-step explanation:
If Rachel earned $34 for 4 hours of work, we must divide the amount earned by the number of hours worked in order to find out her hourly rate and then multiply it by 10 to determine how much she would earn if she worked 10 hours.
She will earn $85 in 10 hours.