Answer:
<u>77.4 degrees and 12.6 degrees</u>
Step-by-step explanation:
Let the angles be x and x - 64.8.
Therefore, on the basis of knowledge that complementary angles add up to 90 degrees :
x + x - 64.8 = 90
2x = 154.8
x = <u>77.4 degrees</u>
x - 64.8 = 77.4 - 64.8 = <u>12.6 degrees</u>
Answer:
-2.5 = x
Step-by-step explanation:
-10 = 4x
the equation between 4 and x is multiplication
as our goal is to move the x on its separate side, we should divide each side by 4 to get rid of the bond between the 4 and the x
Therefore,
-10 = 4x
-10/4 = x
Simplify into decimal if needed
-2.5 = x
Hope that helped!!! k
Answer: The boundary lien should be solid because the inequality indicates that the value “5” is included. Remember: “greater than or equal to; less than or equal to,” as solid lines. While “<;>” are dashed lines.
Answer:10
Step-by-step explanation:
Use the distance formula to determine the distance between two points.
the answer will be 10
Answer:
![(a)\ -16t^2 + 7t + 63=0](https://tex.z-dn.net/?f=%28a%29%5C%20-16t%5E2%20%2B%207t%20%2B%2063%3D0)
![(b)\ t = 2.215](https://tex.z-dn.net/?f=%28b%29%5C%20t%20%3D%202.215)
Step-by-step explanation:
Given
![h(t) = -16t^2 + 7t + 63](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%207t%20%2B%2063)
Solving (a): Equation when it hits the ground.
This means that ![h(t) = 0](https://tex.z-dn.net/?f=h%28t%29%20%3D%200)
So, we have:
![h(t) = -16t^2 + 7t + 63](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%207t%20%2B%2063)
![-16t^2 + 7t + 63=0](https://tex.z-dn.net/?f=-16t%5E2%20%2B%207t%20%2B%2063%3D0)
Solving (b): The value of t in (a)
![-16t^2 + 7t + 63=0](https://tex.z-dn.net/?f=-16t%5E2%20%2B%207t%20%2B%2063%3D0)
Using quadratic formula, we have:
![t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-b%20%5C%C2%B1%20%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
This gives:
![t = \frac{-7 \± \sqrt{7^2 - 4*-16*63}}{2*-16}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%20%5Csqrt%7B7%5E2%20-%204%2A-16%2A63%7D%7D%7B2%2A-16%7D)
![t = \frac{-7 \± \sqrt{49+ 4032}}{2*-16}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%20%5Csqrt%7B49%2B%204032%7D%7D%7B2%2A-16%7D)
![t = \frac{-7 \± \sqrt{4081}}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%20%5Csqrt%7B4081%7D%7D%7B-32%7D)
![t = \frac{-7 \± 63.88}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%2063.88%7D%7B-32%7D)
Split
![t = \frac{-7 + 63.88}{-32}; or\ t = \frac{-7 - 63.88}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%2B%2063.88%7D%7B-32%7D%3B%20or%5C%20t%20%3D%20%5Cfrac%7B-7%20-%2063.88%7D%7B-32%7D)
![t = \frac{56.88}{-32}; or\ t = \frac{-70.88}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B56.88%7D%7B-32%7D%3B%20or%5C%20t%20%3D%20%5Cfrac%7B-70.88%7D%7B-32%7D)
![t = -1.7775; or\ t = 2.215](https://tex.z-dn.net/?f=t%20%3D%20-1.7775%3B%20or%5C%20t%20%3D%202.215)
Time can't be negative; So:
![t = 2.215](https://tex.z-dn.net/?f=t%20%3D%202.215)