Answer:
8.90 M
Explanation:
Step 1: Given data
-
Initial concentration (C₁): ?
- Initial volume (V₁): 635 mL = 0.635 L
- Final concentration (C₂): 5.00 M
- Final volume (V₂): 1.13 L
Step 2: Calculate the initial concentration
We have a concentrated NaCl solution and we want to prepare a diluted one. We will use the dilution rule.
<em>
C₁ × V₁ = C₂ × V₂
</em>
C₁ = C₂ × V₂ / V₁
C₁ = 5.00 M × 1.13 L / 0.635 L
C₁ = 8.90 M
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point
elevation is directly proportional to the molality of the solution
according to the equation: ΔTb = Kb · b.<span>
ΔTb - the boiling point
elevation.
Kb - the ebullioscopic
constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
The relationship between molecular velocities and temperature is a direct relationship. Basically their relationship is directly proportional