Answer:
199920J
Explanation:
Given parameters:
Mass of steam = 85g
Unknown:
Heat released when the liquid is condensed = ?
Solution:
The heat released by the substance is given as;
H = mL
H is the heat released
m is the mass
L is the latent heat of steam = 2352J/g
Heat released = 85 x 2352 = 199920J
The answer is 6 moles of water will be produced.
Answer:
0.5 mole
Explanation:
The question isn't even clear
But I'm guessing you want to ask the number of moles
n= Number of molecules/ Avogadros number
n= 1/2
When calcium carbonate is heated, it breaks down to form calcium oxide and carbon dioxide.
Thermal decomposition is the process in which heat is required.
It is also known as thermolysis.
It is processed in which a compound breaks into two or more products when the heat is supplied.
This reaction is used for the production of oxygen.
This reaction is also used for production of acidic as well as basic oxides.
CaCO3 on thermal decomposition gives:
CaCO3→CaO+CO2
CaO→ Basic oxide.
CO2→ Acidic oxide.
<span>The Atomic Model was something that was first developed by Neils Bohr. Several years later, Schrodinger took Bohr's basis of a theory and developed it into something larger. So as we can see, theories are a bit like puzzles. When first starting out, one person develops something, or has an idea on something. Others trying to either prove or disprove the original findings, will then test things in a new way, revealing more and more of the puzzle. As the puzzle becomes more and more clear, there is more and more that is revealed. Eventually, we get to a point where we have almost the entire picture, however we are still missing a few key pieces that complete the puzzle. We can see the big picture, but you can not exactly prove out what exactly the details are. This is how scientists such as Bohr and Schrodinger use each others research to build and refine theories. Eventually, we reach a point where we are only missing maybe one or two pieces, and at that point, a theory transitions into almost fact, such as evolution.</span>
