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3 years ago

In Balancing Equations, why do I put a 3 before reactant H?

Chemistry

1 answer:

Katena32 [7]3 years ago

5 0

You have 3 (h2(so4)) on the reactants side so you need to have 6 total hydrogen’s on the products side. Therefore 3(h2) is required.

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Explain why pure water has a very slight electrical conductivity.

Pepsi [2]

For electricity to flow there must be a flow of electrons or ions present in a system or medium. When electricity is passed in pure water, oxygen does not have d-orbitals or f-orbitals through which electrons may pass. In pure water there are no electrolytic substance, so no ions present in the pure water. Therefore electricity can not pass through pure water. Additionally; water cannot dissociate into OH- and H+ when electricity is passed through pure water.

7 0

4 years ago

Cerium (IV) ions are strong oxidizing agents in acid ic solution, oxidizing arsenio us acid to arsen ic acid accor ding to the f

kirill [66]

Answer:

0.2042 M is the original concentration of $Ce^{4+}$ (aq) in the titrating solution.

Explanation:

Mass of $As_2O_3$ = 0.217 g

Moles of $As_2O_3=\frac{0.217 g}{198 g/mol}=0.001096 mol$

1 mole of $As_2O_3$ have 2 mole of As and 1 mole of $H_3AsO_3$ have 1 mole of As.

So, from 1 mole of $As_2O_3$ we will have 2 moles of $H_3AsO_3$

Then from 0.001096 mol of $As_2O_3$ :

$2\times 0.001096 mol=0.002192 mol$ of $H_3AsO_3$

$2Ce^{4+}(aq)+H_3AsO_3(aq)+3H_2O(l)\rightarrow 2Ce^{3+}(aq)+H_3AsO_4(aq)+2H^+(aq)$

According to reaction, 1 mole of $H_3AsO_3$ reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of

$\frac{2}{1}\times 0.002192 mol=0.004384 mol$ of cerium (IV) ions.

Volume of the acidic cerium{IV) sulfate = 21.47 ml =0.02147 L

1 mL = 0.001 L

$concentration = \frac{Moles}{Volume(L)}$

$[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M$

0.2042 M is the original concentration of $Ce^{4+}$ (aq) in the titrating solution.

8 0

3 years ago

What is the poH of a 3.67 x 10-5 M OH solution and is it acidic, basic, or neutral?

Anni [7]

Answer:

The pOH is 4, 44 and the solution is basic.

Explanation:

The pOH is a measure of the concentration of OH (hydroxyl) ions in the solution.

The pOH is calculated as :

pOH = -log (OH-)= -log (3.67 x 10-5 )= 4, 44. In this case, the solution is basic.

The p0H scale ranges from values of 0 to 14 (less than 7.0 is basic and greater than 7.0 is acidic, a pH = 7.0 is neutral)

3 0

3 years ago

40 cm3 of acid were mixed with 60 cm3 of alkali in an insulated container. What name is given to this type of reaction?

Stells [14]

Answer:

neutralization reaction

6 0

2 years ago

The atom with the same number of neutrons as 12C is 9Be. 11B. 13C. 14N.

julia-pushkina [17]

Answer : The atom with the same number of neutrons as $^{12}C$ is, $^{11}B$

Explanation :

The given atom is, $^{12}C$

Atomic mass number = 12

Atomic number = 6

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass number - Atomic number = 12 - 6 = 6

Now we have to determine the number of neutrons in the given options.

In atom, $^{9}Be$

Atomic mass number = 9

Atomic number = 4

Atomic number = Number of protons = Number of electrons = 4

Number of neutrons = Atomic mass number - Atomic number = 9 - 4 = 5

In atom, $^{11}B$

Atomic mass number = 11

Atomic number = 5

Atomic number = Number of protons = Number of electrons = 5

Number of neutrons = Atomic mass number - Atomic number = 11 - 5 = 6

In atom, $^{13}C$

Atomic mass number = 13

Atomic number = 6

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass number - Atomic number = 13 - 6 = 7

In atom, $^{14}N$

Atomic mass number = 14

Atomic number = 7

Atomic number = Number of protons = Number of electrons = 7

Number of neutrons = Atomic mass number - Atomic number = 14 - 7 = 7

Therefore, the atom with the same number of neutrons as $^{12}C$ is, $^{11}B$

6 0

3 years ago