1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natka813 [3]
3 years ago
9

Newton's second law states that the force produced by a moving object depends on its mass and acceleration. Which is an example

of this? A. Two boulders move at the same rate of acceleration; the boulder with the smaller mass produces a greater force.
B. Two boulders move at the same rate of acceleration; the boulder with the greater mass produces a greater force.
C. A runner accelerates at a rate of 1 meter per second per second during a race.
Physics
1 answer:
lozanna [386]3 years ago
8 0
The example of Newton's second law is that a runner accelerates at a rate of 1 meter per second per second during the race. The correct answer is C. 
You might be interested in
Assuming a vertical trajectory with no drag, derive the applicable form of the rocket equation for this application
VARVARA [1.3K]

Answer:

The vertical trajectory is governed by Ordinary Differential Equation.

Time derivatives of each state variables.

d(d)/dt = v, d(m)/dt = -d(m-fuel)/dt, d(v)/dt = F/m.

Where V is velocity positive upwards, t is time, m is mass, m-fuel is fuel mass, F is Total force, positive upwards.

Therefore,

F = -mg - D + T, If V is positive and

F = -mg + D - T, If T is negative.

D is drag and the questions gave it as zero.

Explanation:

The two sign cases in derivative equations above are required because F is defined positive up, so the drag D and thrust T can subtract or add to F depending in the sign of V . In contrast, the gravity force contribution mg is always negative. In general, F will be some function of time, and may also depend on the characteristics of the particular rocket. For example, the T component of F will become zero after all the fuel is expended, after which point the rocket will be ballistic, with only the gravity force and the aerodynamic drag force being p

8 0
3 years ago
A magnetic pickup is used to detect the shaft speed of an experimental high speed compressor. a gear with 12 teeth is used to ex
worty [1.4K]
The answer would be 39 seconds
5 0
3 years ago
Read 2 more answers
The _______________ of two objects and their distance from each other determine the gravitational force between them. (Please he
Kryger [21]
" ... product of the masses ... "
8 0
3 years ago
Read 2 more answers
Dans un tube en U contenant du mercure ,on verse de l'autre côté de l'acide sulfurique de densité 1,84 et de l'autre côté de l'a
Iteru [2.4K]

Explanation:

Unclear question. The clear rendering reads;

"Into a U-tube containing mercury, pour on the other side sulfuric acid of density 1.84 and on the other side alcohol of density 0.8 so that the levels are in the same horizontal plane. The height of the acid above the mercury being 24 cm. What is the height of the bar and what variation of the level of the acid, when the mercury density is 13.6?

6 0
3 years ago
A body falls from the top of the tower and during the last second of its fall it fall through 23mvfind height of tower.
DanielleElmas [232]

Answer:

39.7 m

Explanation:

First, we conside only the last second of fall of the body. We can apply the following suvat equation:

s=ut+\frac{1}{2}at^2

where, taking downward as positive direction:

s = 23 m is the displacement of the body

t = 1 s is the time interval considered

a=g=9.8 m/s^2 is the acceleration

u is the velocity of the body at the beginning of that second

Solving for u, we find:

ut=s-\frac{1}{2}at^2\\u=\frac{s}{t}-\frac{1}{2}at=\frac{23}{1}-\frac{1}{2}(9.8)(1)=18.1 m/s

Now we can call this velocity that we found v,

v = 18 m/s

And we can now consider the first part of the fall, where we can apply the following suvat equation:

v^2-u^2 = 2as'

where

v = 18 m/s

u = 0 (the body falls from rest)

s' is the displacement of the body before the last second

Solving for s',

s'=\frac{v^2-u^2}{2a}=\frac{18.1^2-0}{2(9.8)}=16.7 m

Therefore, the total heigth of the building is the sum of s and s':

h = s + s' = 23 m + 16.7 m = 39.7 m

7 0
3 years ago
Other questions:
  • A horse performs 15000 joules of work pulling a wagon for 20 seconds what is the horses power
    7·1 answer
  • Car 1 goes around a level curve at a constant speed of 65 km/h . The curve is a circular arc with a radius of 95 m . Car 2 goes
    15·1 answer
  • A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?
    13·1 answer
  • A car accelerates from rest at a constant rate of 8m/s^2. How fast is it going after 10s? How far has it gone after 10s? What is
    8·1 answer
  • If two swimmers compete in a race, does the faster swimmer develop more power?
    14·1 answer
  • A resistor R and a capacitor C are connected in series to a battery of terminal voltage V0. Which of the following equations rel
    7·1 answer
  • Name the types of motion represented by oA, AB and BC .​
    15·1 answer
  • True or False. Only the initial ball carrier<br><br> can recover a fumble.
    8·2 answers
  • Speed of a train is 5m/s, find its value in km/hr.​
    14·2 answers
  • A small charge q is placed near a large spherical charge Q. The force experienced by both charges is F. The electric eld created
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!