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Agata [3.3K]
3 years ago
13

Please helpers! I wrote the first questions answer but from there i didnt know how to calculate.

Physics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

3.

Force(f) =2000N

Distance (d) =10m

Time(t)=50 sec

We know,

P=W/t

=f×d/t

=2000×10/50

=400 watt

4.

Force(f) =30N

Distance (d) =10 m

Time(t) =5 sec

We know,

P=w/t

=f×d/t

=30×10/5

=60 watt

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A circular coil of wire, with N turns of radius a, is located in the field of an electromagnet. The magnetic field is perpendicu
weeeeeb [17]

Answer:

they are going to attract

Explanation:

7 0
3 years ago
Ở nhiệt độ không đổi, dưới áp suất 10^4 Pa l, một lượng khí có thể tích 10l. Tính thể tích lượng khí đó dưới áp suất 5.10^4 Pa
gtnhenbr [62]

Answer:

Thể tích cuối cùng, V2 = 2 L

Explanation:

Cho các dữ liệu sau đây;

Khối lượng ban đầu = 10 L

Áp suất ban đầu = 10⁴ = 10000 Pa

Áp suất cuối cùng = 5 * 10⁴ = 50000 Pa

Để tìm tập mới hoặc tập cuối cùng, chúng ta sẽ sử dụng định luật Boyle;

Để tìm tập mới V2, chúng tôi sẽ sử dụng định luật Boyles.

Boyles phát biểu rằng khi nhiệt độ của khí lý tưởng được giữ không đổi, áp suất của khí tỉ lệ nghịch với thể tích mà khí chiếm giữ.

Về mặt toán học, định luật Boyles được đưa ra bởi;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Thay vào phương trình, ta có;

10000 * 10 = 50000V_{2}

100000 = 50000V_{2}

V_{2} = \frac {100000}{50000}

V_{2} = 2

Thể tích cuối cùng, V2 = 2 L

6 0
3 years ago
I need this ASAP please!!!
WINSTONCH [101]
It’s E we just had a test in this and I got it right
4 0
3 years ago
Read 2 more answers
What is the mass of an object that has a 250 N force moving at an acceleration of 10 m/s2 ?
zzz [600]
Answer: 25 kg

Identify the given information.
f = 250 N
a = 10 m/s^2 
 
Choose which formula you should use. In this case, you are finding the mass.
The formula for force is f = ma, so, using this, it is easy to find the mass.

f = ma         Divide by a for both sides
m = f/a        Formula for mass!

The formula for mass is m = f/a, where f is force and a is acceleration.

Substitute.
m = (250 N)/(10 m/s^2)
m = 25 kg

5 0
4 years ago
A cubic box of volume 5.1 x 10 -2m3 is
I am Lyosha [343]

Answer:

21544 N

Explanation:

Let the atmospheric pressure be 101325 Pa

The side length of the cubic box:

V = d^3 = 0.051m^3

d = \sqrt[3]{V} = \sqrt[3]{0.051} = 0.371 m

The area of the cubic box:

A = d^2 = 0.371^2 = 0.1375 m^2

20 C = 20 + 273 = 293 K

180 C = 180 + 273 = 453 K

As the volume of the air inside the closed cube is not changed, assume the ideal gas law we have

\frac{P_1}{T_1} = \frac{P_2}{T_2}

Where P1 = 101325 Pa and T1 = 293K are the original atmospheric pressure and temperature. P2 and T2 = 453 are the new pressure and temperature after the cube gets heat up

P_2 = P_1\frac{T_2}{T_1} = 101325\frac{453}{293} = 156656 Pa

The net force on each side of the box it its pressure times side area

F = P_2A = 156656 * 0.1375 = 21544 N

8 0
3 years ago
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