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3 years ago

Explain two reason why SI is easier than the English System.

Physics

1 answer:

kifflom [539]3 years ago

5 0

Answer:

There are several reasons why SI is preferred to the old English system of measurement: ... SI uses base 10, just like our number system, so it is much easier to learn, remember and convert between units. The prefixes used in SI are from Latin and Greek, and they refer to the numbers that the terms represent.

Explanation:

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A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00

Aleksandr-060686 [28]

Answer:

Explanation:

We have the following relation between power, P and intensity, I

$I = P/(4*pi*r^2)$

= $10^3/(4*pi*(35000*10^3))$

= $6.5*10^-14 W/M^2$

We also have the following relationship between electric field and electromagnetic radiation thus

$I = (ceE^2)/2$

Hence $E = \sqrt{2I/ce}$

substituting the values of I, c and e, we have

$7*10^-6 V/m$

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3 years ago

13. Momentum is an object’s mass times velocity. Which has more momentum? A paper airplane with a mass of 10g flying at a veloci

Ivenika [448]

Since the velocity of the real plane is 0, p=mv=0. So the paper airplane actually has more momentum since it's value is not 0.

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3 years ago

g If the interaction of a particle with its environment restricts the particle to a finite region of space, the result is the qu

Travka [436]

Answer:

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Explanation:

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4 years ago

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frosja888 [35]

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3 years ago

Read 2 more answers

Can a goalkeeper at his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance will

zmey [24]

The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

Explanation:

Consider the vertical motion of ball,

We have equation of motion v = u + at

Initial velocity, u = u sin θ

Final velocity, v = 0 m/s

Acceleration = -g

Substituting

v = u + at

0 = u sin θ - g t

$t=\frac{usin\theta }{g}$

This is the time of flight.

Consider the horizontal motion of ball,

Initial velocity, u = u cos θ

Acceleration, a =0 m/s²

Time, $t=\frac{usin\theta }{g}$

Substituting

s = ut + 0.5 at²

$s=ucos\theta \times \frac{usin\theta }{g}+0.5\times 0\times (\frac{usin\theta }{g})^2\\\\s=\frac{u^2sin\theta cos\theta}{g}\\\\s=\frac{u^2sin2\theta}{2g}$

This is the range.

In this problem

u = 30 m/s

g = 9.81 m/s²

θ = 45° - For maximum range

Substituting

$s=\frac{30^2\times sin(2\times 45)}{2\times 9.81}=45.87m$

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.

So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

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3 years ago