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Whitepunk [10]
3 years ago
6

Given f(x) = log2x, which of the functions below represents g(x) resulting from reflecting the graph of f(x) in the x-axis and s

hifting left by 2 units?
Mathematics
2 answers:
enot [183]3 years ago
8 0

Answer:

g(x) = log(2x+2)

Step-by-step explanation:

<em>The question has missing options ; However, the question is still solvable</em>

Given

f(x) = log2x

Direction = 2 units left

Required

Shift the function by 2 units in the x axis

The general format of shifting a function along the x axis (by the left) is as follows

g(x) = log(ax+c)

Where c represents the direction;

c = 2

Since f(x) = log2x, then

g(x) = log(2x+2)

tresset_1 [31]3 years ago
7 0

Answer:

C : g(x) = –log2(x + 2)

Step-by-step explanation:

It's on Edgenuity

Hope this helped :)

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#homework while babysitting help
kaheart [24]

Answer:

1909.57 cm^3

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the following sum of the following expressions: 3x+5 and -4x-10
NeTakaya

Answer:

x + 5

Step-by-step explanation:

3x + 5 -4x - 10

Combine like terms.

-x -5

Divide by -1

x + 5

I hope that this helps! :)

6 0
3 years ago
.Write the quadrants/axes in which the following points lie a) (2,-3) b)(0,8) c)(-1,-2) d)(4,7)
natka813 [3]

Answer:

[see below]

Step-by-step explanation:

Quadrant One has a positive value for both x and y. (+ , +)

Quadrant Two has a negative x value. (- , +)

Quadrant Three has a negative value for both x and y. (- , -)

Quadrant Four has a negative y value.  (+, -)

Therefore:

(2, -3) would be plotted in Q4. It does not lie on any axis.

(0, 8) would be on the positive y-axis. (0 is neither negative nor positive.)

(-1, -2) would be plotted in Q3.  It does not lie on any axis.

(4, 7) would be plotted in Q1.  It does not lie on any axis.

5 0
3 years ago
(50 POINTS AND BRAINLIEST) Show all work to multiply quantity 2 plus the square root of negative 25 end quantity times quantity
xeze [42]
The equation would be (3+√-16)(6-√-64)
A negative square root can not be a real number, meaning that we have to use the imaginary number.
(3+4i)(6-8i)
How to multiply imaginary numbers...
Treat this like an equation looking like (x-a)(y-b)
Use FOIL
(3+4i)(6-8i)
= 18-24i+24i-32i²
= 18-32i²    (i²= -1 because i= √-1)
= 18- (-32)
= 18 + 32
= 50
8 0
3 years ago
Read 2 more answers
Simplify (ab2 + 10 + a) – (6ab2 – 2ab + 8)
grin007 [14]

−5ab2+2ab+a+2

That is the answer if you need more help on other questions use Math-way it helps answer all problems like that

Have a wonderful day love

5 0
2 years ago
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