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Korolek [52]
3 years ago
5

If (a-bi)^2 = 13 - 12i, what is the product of a and b?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

\large \boxed{\sf \ \ \ a\cdot b= 6 \ \ \ }

Step-by-step explanation:

Hello,

(a-bi)^2 = 13 - 12i\\\\ a^2+(bi)^2-2abi = 13-12i\\\\a^2-b^2-2abi=13-12i

Imaginary term must be the same so

-2ab=-12

2ab = 12

ab = 12/2 = 6

So the product of a and b is 6

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Can someone give me the answers plz:)
Alborosie

Remark

There is no short way to do this problem and no obvious way to get the answer other that to solve each part.  

Solve

A

\dfrac{x + 1.6}{2} =\text{x + 0.1}                    Multiply by 2

x + 1.6 = 2(x + 0.1)                                         Remove the brackets

x + 1.6 = 2x + 0.1*2                                        

x + 1.6 = 2x + 0.2                                          Subtract x from both sides

1.6 = x + 0.2                                                  Subtract 0.2 from both sides  

1.6 - 0.2 = x                        

1.4 = x

Circle A

B

Subtract 2x from both sides.

3x - 2x = 1.4

Circle B

C

Remove the brackets.

4x + 6 = 2x - 6           Add 6 to both sides

4x + 12 = 2x               Subtract 4x from both sides.

12 = -2x                      Divide by - 2

12/-2 = x

x = - 6                         Don't circle C

D

I'm going to be very scant in my solution of this. You can fill in the steps.

3x = 4.2

x = 4.2/3

x = 1.4

Circle D

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