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Korolek [52]
3 years ago
5

If (a-bi)^2 = 13 - 12i, what is the product of a and b?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

\large \boxed{\sf \ \ \ a\cdot b= 6 \ \ \ }

Step-by-step explanation:

Hello,

(a-bi)^2 = 13 - 12i\\\\ a^2+(bi)^2-2abi = 13-12i\\\\a^2-b^2-2abi=13-12i

Imaginary term must be the same so

-2ab=-12

2ab = 12

ab = 12/2 = 6

So the product of a and b is 6

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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A rectangle has a length of 12 and a width of 9. What is the
choli [55]

Answer:

15

Step-by-step explanation:

9 squared + 12 squared

3 0
2 years ago
Why is the answer A? Plzzz explain.
Contact [7]

Answer:


Step-by-step explanation:

f(x) = x^2 + 4x + 4

f(x + a) = (x + a)^2 + 4(x + a) + 4

f(x + a) = x^2 + 2ax + a^2 + 4x + 4a + 4   Now combine like terms and use the distributive property.

f(x + a) = x^2 + (2a + 4)x + a^2 + 4a + 4

We are told that f(x + a) = x^2 - 6x + 9

So that means that

2a + 4 = - 6      Subtract 4 from both sides.

2a = - 6 - 4

2a = - 10          Divide by 2

a = - 10/2

a = - 5.            

But you are not finished. You have to check the last part.

a^2 + 4x + 4 = 9

(a + 2)^2 = 9

Take the square root of both sides

sqrt(a+ 2)^2 = +/- 3

a+2 = 3

a = 1.

Does this work or is it extraneous? It is extraneous because it will not work for  2(a) + 4 = - 6  

You get 6 = - 6 which is not correct. But you did give the second best answer.

a + 2 = - 3

a = - 3 - 2

a = - 5 which agrees with your previous answer.

===========

This is an extremely hard or tricky or sneaky problem. It takes a lot of conniving to get the right answer and 1 is not a left field answer. It just does not happen to be correct.

8 0
3 years ago
What is the distance between two points with coordinates at (8, 40) and (20, 5)?
Alchen [17]

Answer:

37 units

Step-by-step explanation:

The two points form a right triangle so

a²+b²=c² so

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12²+35²=c² so

144+1225=c²

1369=c²

c=37 units

7 0
3 years ago
Simplify 1- cos^2 Θ / cos^2 Θ<br><br> Answers<br><br> sin2 θ<br><br> cos2 θ<br><br> tan2 θ<br><br> 1
Tems11 [23]

Answer:

<h3><u /></h3>

<u>Trigonometric identities</u>

<u />

\large \begin{aligned}\cos^2 \theta + \sin^2 \theta & = 1\\\implies \quad \quad \sin^2 \theta & = 1 - \cos^2 \theta\\\\\tan \theta=\dfrac{\sin \theta}{\cos \theta} \end{aligned}

Therefore, using the <u>identities</u>, the given expression can be <em>simplified</em> as follows:

\large\begin{aligned}\implies \dfrac{1- \cos^2 \theta}{\cos^2 \theta} & = \dfrac{\sin^2 \theta}{\cos^2 \theta}\\\\& = \tan^2 \theta\end{aligned}

3 0
2 years ago
Read 2 more answers
Which statement is correct about relations and functions?
vitfil [10]
1. all functions are relations.

2.
-7 + 3(-12) ÷ (-3)
-7 - 36 ÷ -3
-7 - (-12)
-7 + 12
5  

3.
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f(-4) = -4² - (-4)
f(-4) = 16 - (-4)
f(-4) = 16 + 4
f(-4) = 20

hope this helped, God bless!
6 0
3 years ago
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