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Dominik [7]
3 years ago
9

A 1/40 scale model is to be used in a towing tank to study the water motion near the bottom of a shallow channel as a large barg

e passes over . Assume that the model is operated in accordance with the Froude number criteria for dynamic similitude. The prototype barge moves at a typical speed of 13 knots.
(a) At what speed (in ft/s) should the model be towed?
(b) Near the bottom of the model channel a small particle is found to move 0.12 ft in one second so that the fluid velocity at that point is approximately 0.12 ft/s. Determine the velocity at the corresponding point in the prototype channel.
Physics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

I t hi ink the answer is a

Explanation:

I hoped this helpes

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A bus travel with an average velocity of 60km/h. How long does it take to cover a distance of 500km​
Mnenie [13.5K]

Around 8 hours and 20 minutes

Explanation:

I divided 500 by 60 and got 8.3333333333 and i round it up to 8.20, so it is 8 hours and 20 minutes.

8 0
3 years ago
You are camping in the breathtaking mountains if Colorado. You spy an unopened diet soda can floating motionless below the surfa
Pavel [41]

Answer:

C. Up, equal to the can's weight

Explanation:

You are camping in the breathtaking mountains if Colorado. You spy an unopened diet soda can floating motionless below the surface of a lake. What is the direction and amount of force the water exerts on it?

A. Zero

B. Down, equal to the can's weight

C. Up, equal to the can's weight

D. Not enough information is given

from the principle of flotation which states that a

When a body displaces a weight of water equal to its own weight, it floats. : A floating object displaces a weight of fluid equal to its own weight. ... Archimedes' principle equates the buoyant force to the weight of the fluid displaced.

the upthrust (this is the upward vertical force exerted on an object in fluid)in the water equals the weight of the body in water it floats.

7 0
3 years ago
Samanthawalks along a horizontal path in the direction shown the curved path is a semi circle with a radius of 2 m while the hor
Anna11 [10]

Answer:

Explanation:

Samantha walks along a horizontal path in the direction shown the curved path is a semi circle with a radius of 2 m while the horizontal part is for me what is the magnitude of displacement

Displacement is given by the straight line distance between P and Q. Displacement will be length of straight line joining P and Q

a semi circle with a radius of 2 m

Length of this straight line=4+diameter

=4+(2*2)

=8 m

7 0
4 years ago
Please give me answer of this question and I will mark you as brainliest ​
Degger [83]

Answer:

Maharashtra - mashru or himroo / dhoti and lugda

Gujarat - patola / ghagra choli

Punjab - pat / kurta and pajama

Odisha - ikat / Sadi

West Bengal - tossa / kurta

Karnataka - Mysore silk / mundu

6 0
3 years ago
Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.
scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

   Pressure at sea level = 1 atm = 101300 Pa

   we know

   P = ρ g h

   h = \dfrac{P}{\rho\ g}

   h = \dfrac{101300}{1.3\times 9.8}

          h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

  at x = 0  air density = 0

  at x= h   ρ_l = ρ_sl

 assuming density is zero at x - distance

 \rho_x = \dfrac{\rho_{sl}}{h}\times x

now, Pressure at depth x

dP = \rho_x g dx

dP = \dfrac{\rho_{sl}}{h}\times x g dx

integrating both side

P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx

P =\dfrac{\rho_{sl}\times g h}{2}

 now,

h=\dfrac{2P}{\rho_{sl}\times g}

h=\dfrac{2\times 101300}{1.3\times 9.8}

  h = 15902.67 m

height of the atmosphere is equal to 15902.67 m.

6 0
3 years ago
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