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trasher [3.6K]
3 years ago
7

A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be ove

rcome to keep the object moving at a constant velocity?
Physics
1 answer:
jonny [76]3 years ago
4 0

We must remember that the total net force equation at constant velocity is:

<span>F – Ff = 0</span>

of

F - µN = 0

Using Newton's 2nd Law of Motion:<span>

F = m a 

<span>Where,

F = net force acting on the body 
m = mass of the body 
a = acceleration of the body 

Since the cart is moving at a constant velocity, then acceleration is zero, hence the working equation simplifies to 

F = net Force = 0 

Therefore, 

F - µN = 0 

where 

µ = coefficient of friction = 0.20 
N = normal force acting on the cart = 12 N 

Therefore, 

F - 0.20(12) = 0 

<span>F = 2.4 N </span></span></span>
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Answer:

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We know that tangential acceleration is given by the formula \alpha_{t} = r \alpha

Where r =  radius of the disk

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⇒ \alpha_{t} = 0.8 × 50

⇒ \alpha_{t} = 40 \frac{m}{s^{2} }

This is the value of tangential acceleration.

Radial acceleration is given by

\alpha_{r} = \frac{V^{2} }{r}

Where V = velocity of the disk = r \omega

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⇒ V = 8 \frac{m}{s}

Radial acceleration

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\alpha_{r} = 80 \frac{m}{s^{2} }

This is the value of radial acceleration.

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Answer:

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victus00 [196]

The complete question is

What modifications did kepler make to copernicus’s model? check all that apply. planetary orbits are elliptical. planets closer to the sun move faster. planets spin in an epicycle while orbiting earth. venus has phases due to its orbiting of the sun. earth’s rotation causes the rising and setting of the sun.

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