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Lisa [10]
3 years ago
13

Keenan wants to make a paperweight at pottery class. He designs a pyramid-like model with a base area of 808080 square centimete

rs and a height of 7.57.57, point, 5 centimeters. The density of the clay he is using is 1.71.71, point, 7 grams per cubic centimeter.
What is the weight of Keenan's paperweight?
Mathematics
2 answers:
slamgirl [31]3 years ago
8 0

Answer:

<h2>The weight of Keenan's paperweight is 3.33 N.</h2>

Step-by-step explanation:

Givens

  • The base area is 80 square centimeters.
  • The height of the pyramid is 7.5 centimeters.
  • The density of the pyramid is 1.7 grams per cubic centimeters.

First, we find the volume of the figure.

V=\frac{1}{3} (B \times h)

Where B=80cm^{2} and h=7.5 cm.

Replacing values, we have

V=\frac{1}{3}(80)(7.5)=200cm^{3}

The density is defined as

\rho=\frac{m}{V}

Where we need to find the mass m, we already know that \rho=1.7 \ gr/cm^{3} and V=200cm^{3}. Replacing these values, and solving for m

1.7=\frac{m}{200}\\ m=1.7(200)=340 \ gr

Then, we use the weight definition, which is

W=mg

Where m=340 \ gr=0.34 \ kg and g=9.81 m/sec^{2}. Replacing these values, we have

W=0.34(9.81)\\W=3.33 N

Therefore, the weight of Keenan's paperweight is 3.33 N.

iris [78.8K]3 years ago
5 0

Answer:

It is 340

Step-by-step explanation:

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Explanation:-

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Answer:

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Step-by-step explanation:

For example:

{\displaystyle x=y}x=y means that x and y denote the same object.[3]

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quester [9]
To find the surface area of a pyramid, we need to find the area of all the faces and add them up. 

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