Question

Keenan wants to make a paperweight at pottery class. He designs a pyramid-like model with a base area of 808080 square centimeters and a height of 7.57.57, point, 5 centimeters. The density of the clay he is using is 1.71.71, point, 7 grams per cubic centimeter.
What is the weight of Keenan's paperweight?

Answer 1

Answer:

The weight of Keenan's paperweight is 3.33 N.

Step-by-step explanation:

Givens

• The base area is 80 square centimeters.
• The height of the pyramid is 7.5 centimeters.
• The density of the pyramid is 1.7 grams per cubic centimeters.

First, we find the volume of the figure.

$V=\frac{1}{3} (B \times h)$

Where $B=80cm^{2}$ and $h=7.5 cm$.

Replacing values, we have

$V=\frac{1}{3}(80)(7.5)=200cm^{3}$

The density is defined as

$\rho=\frac{m}{V}$

Where we need to find the mass $m$, we already know that $\rho=1.7 \ gr/cm^{3}$ and $V=200cm^{3}$. Replacing these values, and solving for $m$

$1.7=\frac{m}{200}\\ m=1.7(200)=340 \ gr$

Then, we use the weight definition, which is

$W=mg$

Where $m=340 \ gr=0.34 \ kg$ and $g=9.81 m/sec^{2}$. Replacing these values, we have

$W=0.34(9.81)\\W=3.33 N$

Therefore, the weight of Keenan's paperweight is 3.33 N.

Answer 2

Answer:

It is 340

Step-by-step explanation: