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jonny [76]
3 years ago
13

How many helium nuclei fuse together when making carbon?

Chemistry
1 answer:
Gemiola [76]3 years ago
8 0
The answer is the 3. Hope this helped!
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What is 11/6 + 11/6 in fractions
Andreyy89
3 2/3 is your answer
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Read 2 more answers
Which particles have a similar relative mass
olganol [36]

Answer:

c ) protons and neutrons

Explanation:

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron). The positive charge on a proton is equal in magnitude to the negative charge on an electron.

7 0
3 years ago
Find the density of an object that has a mass of 12.69 grams and a volume of 3.5cm3
lutik1710 [3]

Answer:

3.62 g/cm³

Explanation:

density = mass ÷ volume

Therefore, do 12.69 divided by 3.5

6 0
3 years ago
Pls help me. Show proof on why it’s that answer.
natulia [17]
The answer is “the sustainability of the ecosystem” because if the ecosystem isn’t sustainable enough for many different organisms to live in it then the biological diversity of the ecosystem will decrease.
6 0
3 years ago
Consider an amphoteric hydroxide, m(oh)2(s), where m is a generic metal. estimate the solubility of m(oh)2 in a solution buffere
Colt1911 [192]
Missing data in your question: (please check the attached photo)
from this balanced equation:
M(OH)2(s) ↔ M2+(aq) + 2OH-(aq) and when we have Ksp = 2x10^-16
∴Ksp = [M2+][OH]^2
2x10^-16 = [M2+][OH]^2
a) SO at PH = 7 
∴POH = 14-PH = 14- 7 = 7
when POH = -㏒[OH]
7= -㏒[OH]
∴[OH] = 1x10^-7 m by substitution with this value in the Ksp formula,
∴[M2+] =Ksp /[OH]^2
            = (2x10^-16)/(1x10^-7)^2
             = 0.02 M
b) at PH =10
when POH = 14- PH = 14-10 = 4 
when POH = -㏒[OH-]
            4  = -㏒[OH-]
∴[OH] = 1x10^-4 ,by substitution with this value in the Ksp formula
[M2+] = Ksp/ [OH]^2
          = 2x10^-16 / (1x10^-4)^2
          = 2x10^-8 M
c) at PH= 14 
when POH = 14-PH
                   = 14 - 14 
                   = 0
when POH = -㏒[OH]
              0 = - ㏒[OH]
∴[OH] = 1 m 
by substitution with this value in Ksp formula :
[M2+] = Ksp / [OH]^2
          = (2x10^-16) / 1^2
          = 2x10^-16 M


8 0
3 years ago
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