It is 95% ethanol and 5%water
I’m pretty sure hope you get it right!
:)
Answer : Half reaction is defined as the reaction which will be <span>either the oxidation or reduction </span>reaction<span> of particular species in a given redox </span>reaction<span>.
So as per the definition in the reaction of,
</span>
<span>
</span>
<span>
here on left and right side </span>
will get cancelled.
and we will get,
Here,
...this is oxidation reaction as Ba is getting reduced to
by losing 2 electrons.
whereas,on the other hand,
...this is reduction reaction as
is getting reduced to Zn by gaining 2 electrons.
Answer:
Explanation:
16. 12
17. 8
18. 9
19. 10
20. 5
21. 15
22.8
23. 24
24. 12
25. 3 i guess( some one comment for 25th pls)
26. 2
Answer is: <span>requirement of valine is 0,0222 mol for a100 kilograms adult.
</span>m(C₅H₁₁NO₂) = 2,60 g.
M(C₅H₁₁NO₂) = 5 · 12 + 11 · 1 + 1 · 14 + 2 · 16 · g/mol.
M(C₅H₁₁NO₂) = 117 g/mol.
n(C₅H₁₁NO₂) = m(C₅H₁₁NO₂) ÷ M(C₅H₁₁NO₂).
n(C₅H₁₁NO₂) = 2,60 g ÷ 117 g/mol.
n(C₅H₁₁NO₂) = 0,0222 mol.
n - amount of substance.
m - mass of substance.
M - molar mass of substance.
Answer: First, here is the balanced reaction: 2C4H10 + 13O2 ===> 8CO2 + 10H2O.
This says for every mole of butane burned 4 moles of CO2 are produced, in other words a 2:1 ratio.
Next, let's determine how many moles of butane are burned. This is obtained by
5.50 g / 58.1 g/mole = 0.0947 moles butane. As CO2 is produced in a 2:1 ratio, the # moles of CO2 produced is 2 x 0.0947 = 0.1894 moles CO2.
Now we need to figure out the volume. This depends on the temperature and pressure of the CO2 which is not given, so we will assume standard conditions: 273 K and 1 atmosphere.
We now use the ideal gas law PV = nRT, or V =nRT/P, where n is the # of moles of CO2, T the absolute temperature, R the gas constant (0.082 L-atm/mole degree), and P the pressure in atmospheres ( 1 atm).
V = 0.1894 x 0.082 x 273.0 / 1 = 4.24 Liters.
Explanation:
