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3 years ago

Which element is a liquid at STP? (1) argon (3) chlorine (2) bromine (4) sulfur

Chemistry

2 answers:

OlgaM077 [116]3 years ago

5 0

Since chlorine and argon are propellant and sulfur is solid. Then the answer is 2) Bromine.

SashulF [63]3 years ago

5 0

Answer: Option (2) is the correct answer.

Explanation:

STP means standard temperature and pressure.

At STP chlorine exists as a gas, sulfur exists as a solid and argon also exists as a gas.

Whereas bromine exists as a liquid at STP.

Thus, we can conclude that out of the given options bromine is the element which exists as a liquid at STP.

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Dinitrogen tetraoxide is a colorless gas at room temperature. It can dissociate into nitrogen dioxide, which is a reddish brown

Alenkinab [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The calculation and filling of the table based on the ratio indicated by the column is shown on the second uploaded image

1 This is True

2 This is False

3 This is False

4 This is True

5 This is True

Explanation:

Based on your calculations, indicate whether each statement is True (T) or False (F):

Considering the first statement

Looking at the question we can see that the first statement is TRUE this because all the three experiment have different initial concentration (3.5,3.0 & 2.6)

Considering the second statement

Looking at table we can see that the second statement is FALSE because

the ratio value of [NO2]/ [N2O4] in all three experiment have different value 1.4 , 1.5 & 1.7 is not a constant value.

Considering the Third statement

Looking at the table we can see that the third statement is FALSE this is because the ratio value of 2[NO2]/ [N2O4] in all three experiment have different value 2.7, 3.0 & 3.3 is not a constant value.

Considering the Fourth statement

Looking at table we can see that the fourth statement is TRUE this is because the ratio value of $[NO2]^{2}/ [N2O4]$ in all three experiment have same value 3.9, 3.9 & 3.9 is a constant value.

Considering the Fifth statement

Looking at table we can see that the fifth statement is TRUE this is because

each having different set of Equilibrium concentration

3 0

4 years ago

To calculate the Ksp of 0.34 g of cesium sulfate (Cs2SO4) in 1.00 L of aqueous solution, which equilibrium equation will you use

FinnZ [79.3K]

Answer:C

Explanation:

5 0

3 years ago

Inessa [10]

Answer:

methane + oxygen → carbon dioxide + water

Explanation:

methane + oxygen → carbon dioxide + water

5 0

3 years ago

Almost done somebody please help me

s344n2d4d5 [400]

The correct answer is A. It is uniform in composition and the parts that make up the mixture can be separated from one another through physical means.

Explanation:

In a homogeneous mixture, components are completely integrated, which means the final substance is uniform and the parts that compose it are not separated. This occurs in milk because this integrates uniformly water, fat, among others, and these elements cannot be observed separately.

Moreover, in mixtures, components can be separated through physical means; for example by heating the substances. This applies to milk because if it is heated water evaporates, and therefore can be separated.

6 0

4 years ago

What is the orientation of the two unhybridized p orbitals on Be with respect to the two Be−F bonds?

Len [333]

Answer:

b) Both p orbitals are perpendicular to the F−Be−F bond axes.

Explanation:

Be has 2 electrons in its valence shell, subshell s is fulfilled, so it has no unpaired electrons in its ground state to make bonds with F. So, it can promote the electrons to the 2p orbital and will having sp hybridization.

The bond between the orbitals sp and the p orbital of F are in opposite directions but the same ax. The two bonds are equivalent, and the molecule had a linear geometry. The two unhybridized p orbitals on Be are vacant, and so they are perpendicular to the F-Be-F bond axes.

7 0

4 years ago