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alukav5142 [94]
2 years ago
7

Which is a possible heat capacity for a bomb calorimeter?

Chemistry
1 answer:
Leona [35]2 years ago
7 0
B. i took the test and got it right
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When water is electrolyzed, it splits into hydrogen and oxygen.
Westkost [7]

The mass of water is equal to the combined mass of hydrogen and oxygen.

<h3>What is Mass?</h3>

This is defined as the quantity of matter in a physical body. The electrolysis reaction of water can be seen below:

2 H₂O ---> 2 H₂ + O₂

We can deduce that 36 grams of H₂O dissociated to give 4 grams of H₂ and 32 grams of O₂ which option D was chosen as the appropriate choice.

Read more about Mass here brainly.com/question/25121535

4 0
2 years ago
Most of our DNA consists of regions that do not code for any proteins True or False
Lady bird [3.3K]
The Answer you are looking for is true
5 0
3 years ago
Arrange the following element, lithium, potassium, carbon and fluorine in increasing ionization energy
Juli2301 [7.4K]

Answer:

flourine(1681),carbon(1086),lithium(520) and potassium(419)

as we can see that the ionization energy of flourine is the highest than carbon than lithium and than potassium

Explanation:

i hope it will help you

4 0
3 years ago
Read 2 more answers
Paul has different spoons for cooking. He told Sue that he likes to stir hot food with a wooden spoon because it does not burn h
IceJOKER [234]

Answer:

Sue was not right as wood is not a heat conductor and will not allow heat to pass through the spoon thus keeping the hand safe. In a meatal spoon, heat can pass through and burn the hand as meatal is a good conductor of heat.

8 0
3 years ago
n unknown metal is either aluminum, iron or lead. If 150. g of this metal at 150.0 °C was placed in a calorimeter that contains
Nitella [24]

Answer : The metal used was iron (the specific heat capacity is 0.449J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of unknown metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of unknown metal = 150 g

m_2 = mass of water = 200 g

T_f = final temperature of water = 34.3^oC

T_1 = initial temperature of unknown metal = 150.0^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

150g\times c_1\times (34.3-150.0)^oC=-200g\times 4.184J/g^oC\times (34.3-25.0)^oC

c_1=0.449J/g^oC

Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).

Therefore, the metal used was iron (the specific heat capacity is 0.449J/g^oC).

6 0
4 years ago
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