nearly 68 percent of American homes were electrified. But, if you don't count farms, about 85 percent of Americans had electricity by the end of the 1920s.
And there's the rub. Rural communities, including farms, were far slower in adopting electricity than the rest of the country. Of the roughly 6.3 million American farms in 1922, only about 3% had electricity. It wasn't until 1935 that the U.S. government addressed this huge rural vs urban electric divide with the formation of the Rural Electrification Administration.
Hello from MrBillDoesMath!
Answer: 21
Discussion:
g(3) = 3^2 -2 = 9 -2 = 7 =>
f(g(3)) = f (
7) = 2(7) + 7 = 14 + 7 = 21
Thank you,
MrB
Answer:
13
Step-by-step explanation:
4 + 3(x + 5)=5 x - 7
3x + 19=5x - 7
3x + 19 - 19=5x - 7 - 19
3x =5x - 26
3x - 5x=5x - 26 - 5x
-2= -26
-2x/-2 = -26/-2
x= 13
It might be wrong. I may have made a mistake with typing sorry.
Hope this helps a bit.
15=-4+z/3
+4 +15 = +4 -4 +z/3
cancels the 4 on the right side
19 = z/3
3 x 19 = z/3 x 3
cancels 3 on the right side
I think the answer is z = 57
Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
