Question

A driver who does not wear a seatbelt continues to move forward with a speed of 18.0 m/s (due to inertia) until something solid like the steering wheel is encountered. The driver now comes to rest in a much shorter distance-perhaps only a few centimeters. Find the magnitude of the net force acting on a 65.0 kg driver who is decelerated from 18.0 m/s to rest in 5.00 cm. A driver who does not wear a seatbelt continues to move forward with a speed of 18.0 (due to inertia) until something solid like the steering wheel is encountered. The driver now comes to rest in a much shorter distance-perhaps only a few centimeters. Find the magnitude of the net force acting on a 65.0 driver who is decelerated from 18.0 to rest in 5.00 . F=3240N F=1.173×104N F=2.113×105N F=4.213×105N

Answer 1

Answer:

F = 2.113 x 10⁵ N

Explanation:

First we need to calculate the deceleration of the driver by using 3rd equation of motion:

2as = Vf² - Vi²

where,

a = deceleration = ?

s = distance = 5 cm = 0.05 m

Vf = Final Velocity = 0 m/s

Vi = Initial Velocity = 18 m/s

Therefore,

2a(0.05 m) = (0 m/s)² - (18 m/s)²

a = (- 324 m²/s²)/0.1 m

a = - 3240 m/s²

where, negative sign represents deceleration

From Newton's Second Law of Motion:

F = ma

F = (65 kg)(-3240 m/s²)

F = - 2.106 x 10⁵ N

So, he closest answer is:

F = 2.113 x 10⁵ N