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Yakvenalex [24]
3 years ago
11

Stretching is important prior to physical activity and a few hours after/the next day after. What does stretching accomplish whi

ch is important in preventing some injuries?
Extends muscles and limbs to their full extent.

Works those muscles now so I can take it easy during my activities and not work as long/as hard.

Creates pain now instead of later.

Extends muscles and limbs to their full extent providing increased blood flow and flexibility to prepare for physical activity.
Physics
1 answer:
Ann [662]3 years ago
3 0
The last one is correct
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Two tougboats are toeing a ship each exerts a force of 6000N and the angle between the two ropes is 60 calculate the resultant f
Arlecino [84]

Answer:

10392.30N

Explanation:

We proceed by computing the individual force exerted by the boats

For the first boat

The angle is 30 degree to the vertical

Hence

Force = F cos θ

F=6000 cos 30

F=6000*0.866

F=5196.15 N

Since the boats are two and also at the same angle and also exerting the same force

The Net force = 2*5196.15

Net force=10392.30N

7 0
2 years ago
How many times smaller is the moon than earth?
Yuki888 [10]
The moon has approximately 1/4 of earths diameter, 1/50 of earths volume and 1/80 of earths mass
3 0
3 years ago
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1. A ball initially rolling at 10m/s comes to a stop in 25 seconds. Assuming the ball has
LiRa [457]

Answer:

B) 125 m

Explanation:

s =  \frac{u + v}{2} t \\ s \:  =  \frac{10 + 0}{2} (25) \\ s \:  = 125m

5 0
3 years ago
The relationship between mass and inertia is described by newton's second law of motion. true or false
Mariana [72]
False. Inertia and mass is not described in Newton’s second law of motion but in Newton’s first law of motion. Newton’s first law of motion or sometimes referred to as the law of inertia. In Newton’s first law indicates that an object at rest will remain at rest unless acted by an unbalanced force. An object in motion continues in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
4 0
3 years ago
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 2.5 s
gulaghasi [49]

(a) 0.96 m/s

The period of the wave corresponds to the time taken for one complete oscillation of the boat, from the highest point to the highest point again. Since the time between the highest point and the lowest point is 2.5 s, the period is twice this time:

T=2\cdot 2.5 s=5.0 s

The frequency of the waves is the reciprocal of the period:

f=\frac{1}{T}=\frac{1}{5.0 s}=0.20 Hz

The wavelength instead is just the distance between two consecutive crests, so

\lambda=4.8 m

And the wave speed is given by:

v=\lambda f=(4.8 m)(0.20 Hz)=0.96 m/s

(b) 0.265 m

The total distance between the highest point of the wave and its lowest point is

d = 0.53 m

The amplitude is just the maximum displacement of the wave from the equilibrium position, so it is equal to half of this distance. So, the amplitude is

A=\frac{d}{2}=\frac{0.53 m}{2}=0.265 m

(c) Amplitude: 0.15 m, wave speed: same as before

In this case, the amplitude of the wave would be lower. In fact,

d = 0.30 m

So the amplitude would be

A=\frac{d}{2}=\frac{0.30 m}{2}=0.15 m

Instead, the wave speed would not change, since neither the frequency nor the wavelength of the wave have changed.

8 0
3 years ago
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