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Advocard [28]
3 years ago
6

In what way would a digital thermometer be preferable to those from a liquid-based thermometer?

Physics
1 answer:
garik1379 [7]3 years ago
5 0
Reading a digital thermometer is more preferable because you can just easily read the measurement from a screen, a number will just show in a screen as compared to a liquid-based thermometer where you still have to read the measurement by counting the markers in the thermometer. Hope this helps! Mark brainly please!
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What is a good question for a Science Fair (7th grade advanced) also im an online student so nothing really physical something t
tia_tia [17]
Photosynthesis is a good one you can really explain with pictures
8 0
3 years ago
Determine if the data are qualitative, quantitative, or neither. Zinc is a silver-gray metal. Chlorine has a density of 3.2 g/L.
AysviL [449]

Qualitative data gives the information of quality which can not be measured in numbers. For example: Color of eyes, softness of skin.

Quantitative data is information of quantity that can be represented in numbers. For example length and mass of any object.

Zinc is a silver-gray metal is a qualitative data, here silver gray color is quality of zinc metal which can not be measured in numbers.

Chlorine has a density of 3.2 g/L is a quantitative data. The value of density can be compared with other elements by comparing the numbers.

Gallium is not found in nature is neither qualitative nor quantitative.

Nitrogen has a melting point of –210.00 °C is a quantitative data because this is expressed in numbers.

Aluminum is a solid is a qualitative data because it tells about the state of element which can not be measured in numbers.


5 0
3 years ago
Read 2 more answers
What is the part of the cell that stores food?
Alenkasestr [34]
Part of the cell that stores food is called vacuole
3 0
3 years ago
If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?
steposvetlana [31]

Hi there!

\large\boxed{\text{B) 20 meters}}

We know that:

E_T = U + K

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

<u>h = 20 meters</u>

3 0
2 years ago
What is the centripetal acceleration of the earth as it travels around the sun when Earth has an orbital radius of 1.5 x 10^11 m
masya89 [10]

Answer: 0.0058 m/s^{2}

Explanation:

Centripetal acceleration a_{C} is calculated by the following equation:

a_{C}=\frac{V^{2}}{r}

Where:

V=29.7 \frac{km}{h} \frac{1000 m}{1 km}=29700 m/s is the Earth's orbital speed

r=1.5(10)^{11} m is the orbital radius

a_{C}=\frac{(29700 m/s)^{2}}{1.5(10)^{11} m}

a_{C}=0.0058 m/s^{2}

4 0
3 years ago
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