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Natalija [7]
3 years ago
10

A particle with a charge of +4.0 μC has a mass of 5.0 g. What magnitude electric field directed upward will exactly balance the

weight of the particle?
Physics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

E = 12262 V/m

Explanation:

given,

Charge of the particle, q = +4.0 μC

mass of the ball, m = 5 g

Electric field, E = ?

Force due to weight

F = m g

Force due to electric field

F =q E

To balance the weight of particle both the forces must be equal

Electric field exerted on the ball will be equal to

m g = q E

E = \dfrac{m\ g}{q}

E = \dfrac{5\times 10^{-3}\times 9.81}{4\times 10^{-6}}

E = 12262 V/m

Hence, the electric field acting in the particle is equal to E = 12262 V/m

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A stone is dropped into a well. The sound of the splash is heard 6.25 s later. What is the depth of the well? (Take the speed of
Naya [18.7K]

Answer:

depth of well is 163.30 m

Explanation:

Given data

speed of sound = 343 m/s

timer = 6.25 s

to find out

depth of well

solution

let us consider depth d

so equation will be

depth = 1/2 ×g ×t²    ..............1

and

depth = velocity of sound × time    .................2

here we have given time 6.25 that is sum of 2 time

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so time 1 + time 2 = 6.25 s

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