A particle with a charge of +4.0 μC has a mass of 5.0 g. What magnitude electric field directed upward will exactly balance the
1 answer:
Answer:
E = 12262 V/m
Explanation:
given,
Charge of the particle, q = +4.0 μC
mass of the ball, m = 5 g
Electric field, E = ?
Force due to weight
F = m g
Force due to electric field
F =q E
To balance the weight of particle both the forces must be equal
Electric field exerted on the ball will be equal to
m g = q E
E = 12262 V/m
Hence, the electric field acting in the particle is equal to E = 12262 V/m
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There isn't a direct answer to this, but I can show you!
This is how you group Pennies, Nickels, and Dimes.
1 Penny= 1 cent.
1 Nickel= 5 cents.
1 Dime= 10 cents.
Imagine if there was 5 pennies, 3 dimes, and 8 Nickels.
That might seem like a lot of numbers, but it's pretty simple!
You know how pennies are worth 1 cent? If we had 5 pennies, that would be 5 cents.
1+1+1+1+1=5 cents.
Then, we have 3 dimes. Dimes are each 10 cents.
So, 10x3 (If you know multiplication, if not, you will learn it later) :)
10+10+10= 30 cents.
Now, nickels. We have 8 nickels! Remember, each nickel is 5 cents.
5+5+5+5+5+5+5+5=
40 Nickels.
Now add all of the coins up.
5 cents + 30 cents + 40 cents = 75 cents!
I hope this helped! If you need more help, you can ask me. :)
