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KonstantinChe [14]
4 years ago
14

What are the phenomena that physics in applied in ?​

Physics
1 answer:
Deffense [45]4 years ago
3 0

Answer:

For empiricists like van Fraassen, the phenomena of physics are the appearances observed or perceived by sensory experience. Constructivists, however, regard the phenomena of physics as artificial structures generated by experimental and mathematical methods.

Explanation:

<h3>I hope it's help u </h3><h3>Have a great day </h3>
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Four forces act on bolt A as shown; F1 150N, F2 80N, F3 110N and F4 100N. Determine the magnitude and direction of the resultant
netineya [11]

Complete Question

The  complete question(reference (chegg)) is shown on the first uploaded image

Answer:

The magnitude of the resultant force is  F  =  199.64 \ N

The  direction of the resultant force is  \theta  =  4.1075^o from the horizontal plane

Explanation:

Generally when resolving force, if the force (F )is moving toward the angle then the resolve force will be  Fcos(\theta ) while if the force is  moving away from the angle  then the resolved force is  Fsin (\theta )

Now  from the diagram let resolve the forces to their horizontal component

    So

          \sum F_x  =  150 cos(30) + 100cos(15) -80sin (20)

          \sum F_x  =  199.128 \ N

Now  resolving these force into their vertical component can be mathematically evaluated as

         \sum  F_{y}  =  150 sin(30) - 100sin(15) -110 +80 cos(20)

         \sum  F_{y}  =  14.30

Now the resultant force is mathematically evaluated as

        F  =  \sqrt{F_x^2 + F_y^2}

substituting values

        F  =  \sqrt{199.128^2 + 14.3^2}

        F  =  199.64 \ N

The  direction of the resultant force is  evaluated as

       \theta  =  tan^{-1}[\frac{F_y}{F_x} ]

substituting values

       \theta  =  tan^{-1}[\frac{ 14.3}{199.128} ]

       \theta  =  4.1075^o from the horizontal plane

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Explanation:

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