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3 years ago

What are the phenomena that physics in applied in ?

Physics

1 answer:

Deffense [45]3 years ago

3 0

Answer:

For empiricists like van Fraassen, the phenomena of physics are the appearances observed or perceived by sensory experience. Constructivists, however, regard the phenomena of physics as artificial structures generated by experimental and mathematical methods.

Explanation:

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I need help find how much tension is in the string????

Nikitich [7]

Answer:

When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Image result for I need help find how much tension is in the string???? And can you explain how you got it after you get the answer plz????

Hence, in such a case the tension will be equal to the centrifugal force.

Formula for tension = centrifugal force = mv2/r.

So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)

The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)

Explanation:

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3 years ago

You hold a small metal ball of mass a height above the floor. You let go, and the ball falls to the floor. Choose the origin of

baherus [9]

Answer:

yᵢ = h

vᵢᵧ = 0

Explanation:

Let initial velocity = u

final velocity = v

height = h

acceleration due to gravity = g

Therefore fro equation of motion,

$v^{2}=u^{2}+2gh$

Here initial velocity is zero.

Hence, $v^{2}=2gh$

$v = \sqrt{2gh}$

but since it points downward and you positive is taken in the up direction

$v = -\sqrt{2gh}$

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4 years ago

The weight of an object is the same on two different planets. The mass of planet A is only sixty percent that of planet B. Find

natka813 [3]

Answer:

0.775

Explanation:

The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:

$F=G\frac{Mm}{R^2}$

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

For planet A, the weight of the object is

$F_A=G\frac{M_Am}{R_A^2}$

For planet B,

$F_B=G\frac{M_Bm}{R_B^2}$

We also know that the weight of the object on the two planets is the same, so

$F_A = F_B$

So we can write

$G\frac{M_Am}{R_A^2} = G\frac{M_Bm}{R_B^2}$

We also know that the mass of planet A is only sixty percent that of planet B, so

$M_A = 0.60 M_B$

Substituting,

$G\frac{0.60 M_Bm}{R_A^2} = G\frac{M_Bm}{R_B^2}$

Now we can elimanate G, MB and m from the equation, and we get

$\frac{0.60}{R_A^2}=\frac{1}{R_B^2}$

So the ratio between the radii of the two planets is

$\frac{R_A}{R_B}=\sqrt{0.60}=0.775$

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3 years ago

What is the vertical acceleration of a paper airplane that is launched horizontally with an initial velocity of 2.3 m/s?

serious [3.7K]

A. ) -9.8 m/s2 is the correct answer.

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3 years ago

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Weight of a man is less at coal mine.Why?

dmitriy555 [2]

If someone is underground, then therefore there is less planet/ground underneath them, so there would be less gravity. Gravity directly affects weight.

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3 years ago

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What are the phenomena that physics in applied in ?​

What are the phenomena that physics in applied in ?