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Butoxors [25]
3 years ago
8

A device has a least count of 0.01m if it measures a length less than 100m the minimum and maximum number of significant figure

are
a)1 and 2
B)2 and 3
C)1 and 4
D) 0 and 2
Physics
1 answer:
Klio2033 [76]3 years ago
5 0

Answer:

C) 1 and 4

Explanation:

Least count is .01 m . If one measures any number between 100 and 99 , it will be like 99.25 or 99.37 m . So number of significant figure will be 4 ( maximum )

The least one can measure is .01 so least number of significant figure possible is 1 .

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The box leaves position x=0 with speed v0. The box is slowed by a constant frictional force until it comes to rest at position x
Diano4ka-milaya [45]

Answer:

Ff=m\times \dfrac{V_o^2}{2X_1}

Explanation:

Given that

At X=0 V=Vo

At X=X1  V=0

As we know that friction force is always try to oppose the motion of an object. It means that it provide acceleration in the negative direction.

We know that

V^2=U^2-2aS

0=V_o^2-2a X_1

a=\dfrac{V_o^2}{2X_1}

So the friction force on the box

Ff= m x a

Ff=m\times \dfrac{V_o^2}{2X_1}

Where m is the mass of the box.

4 0
3 years ago
What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms
kirza4 [7]

Answer:

F' = (3/2)F

Explanation:

the formula for the electric field strength is given as follows:

E = F/q

where,

E = Electric Field Strength

F = Force due to the electric field

q = magnitude of charge experiencing the force

Therefore,

F = E q   ---------------- equation (1)

Now, if we half the electric field strength and make the magnitude of charge triple its initial value. Then the force will become:

F' = (E/2)(3 q)

F' = (3/2)(E q)

using equation (1)

<u>F' = (3/2)F</u>

3 0
3 years ago
A 100 kg bungee jumper leaps from a bridge. The bungee cord has an un-streched equilibrium length of 10 m, and a spring constant
nika2105 [10]

Answer:

11.78meters

Explanation:

Given data

Mass m = 100kg

Length of cord= 10m

Spring constant k= 35N/m

At the greatest vertical distance, the spring potential energy is equal to the gravitational potential energy

That is

Us=Ug

Us= 1/2kx^2

Ug= mgh

1/2kx^2= mgh

0.5*35*10^2= 100*9.81*h

0.5*35*100=981h

1750=981h

h= 1750/981

h= 1.78

Hence the bungee jumper will reach 1.78+10= 11.78meters below the surface of the bridge

6 0
3 years ago
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steposvetlana [31]

Yes, eg., when 2 bodies move in opposite directions

, the relative velocity of each is greater than the individual velocity of either

8 0
3 years ago
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