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nirvana33 [79]
3 years ago
15

What is the density of a 14.4 g of chromium in a rectangle with a volume of 2 cm3?​

Physics
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

density =  \frac{mass}{volume}  \\  \\ density =  \frac{14.4}{2}  \\  \\ { \boxed{ \boxed{density = 7.2 \: g {cm}^{ - 3} }}}

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Three solid, uniform, cylindrical flywheels, each of mass 65.0 kg and radius 1.47 m, rotate independently around a common axis t
Mkey [24]

Answer:

the angular momentum is 1015.52 kg m²/s

Explanation:

given data

mass of each flywheel, m = 65 kg

radius of flywheel, r = 1.47 m

ω1 = 8.94 rad/s

ω2 = - 3.42 rad/s

to find out

magnitude of the net angular momentum

solution

we get here Moment of inertia that is express as

I = 0.5 m r²    .................1

put here value and we get

I = 0.5 × 65 × 1.47 × 1.47

I = 70.23 kg m²

and

now we get here Angular momentum that is express as

L = I × ω    ...........................2

and Net angular momentum will be

L = 2 × I x ω1 - I × ω2

put here value and we get

L = 2 × 70.23 × 8.94 - 70.23 × 3.42

L = 1015.52 kg m²/s

so

the angular momentum is 1015.52 kg m²/s

3 0
4 years ago
How do you solve this scientific notation question?
podryga [215]

factorise 1/10^2 out of both.

add 1/4.5 to 1/9.4 .... common denominator  4.5x9.4

multiply result by 1/10^2

find reciprocal of result

phew !

8 0
3 years ago
The black hole is___<br> times smaller that the star.<br> I need answers please
mojhsa [17]

Answer:

The answer is 24 (for the first question).

Explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
3 0
3 years ago
You volunteer for chalkboard cleaning duty and you get to work with the erasers. As you rub the dust off of the chalkboard, whit
Anna71 [15]

Answer:

A physical change

Explanation:

You are wiping chalk particles from the board to the eraser which is just changing the location of the chalk particles, a physical change.

you're not changing the chalk into a new substance or causing a chemical reaction, which would be a chemical change.

3 0
4 years ago
A syringe containing 1.55 ml of oxygen gas is cooled from 95.3 °c to 0.0 °c. what is the final volume of oxygen gas?\
irinina [24]
Consider the gas to be an ideal gas (it will obey all the introductory gas laws). Also you have to note that the gas will not change phase. It won't.

T_s (Temperature Start) = 95.3o C = 95.3 + 273 = 368.3 oK (degrees Kelvin)
T_e (Temperature End) = 0o C + 273 = 273 oK

Initial volume = Vi = 1.55 mL (no need to change to Liters. The answer will be in mL

 Vi /Ts =  Ve / Vs Ve is the unknown volume that you seek.
1.55 / 368.3  =  Ve / 273
Ve = 1.55 * 273 / 368.3
Ve = 1.1489 mL

If your teacher is concerned about Sig digs, then 0.0 has only two.
Your answer should be 1.1 mL, but I'll give you the choice.



3 0
4 years ago
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