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S_A_V [24]
3 years ago
5

In an automobile collision, a 44-kilogram passenger moving at 15 meters per second is brought to rest by an air bag during a 0.1

0-second time interval. What is the magnitude of the average force exerted on the passenger during this time?
Physics
1 answer:
const2013 [10]3 years ago
8 0

Answer:

6,600N

Explanation:

According to second law of motion, Force = mass × acceleration

If acceleration = change in velocity/time = 15/0.10

Acceleration = 150m/s²

Given mass = 44kg

Force = 44× 150

Force = 6,600N

Magnitude of the average force exerted on the passenger during this time is 6,600N

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Explanation:

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3 years ago
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

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Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

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a = - 0.83 m/s²

Then, imputing the value of a into

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F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

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3 0
3 years ago
What's a difference between mercury and oxygen?<br> (They both are elements)
borishaifa [10]

--  There are 80 protons in the nucleus of every atom of Mercury,
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--  Mercury must be colder than -39°C in order to freeze, but Oxygen
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4 years ago
What is the acceleration if we speed up from 10m/s to 30 m/s in 10 seconds
lina2011 [118]
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Hope this helps! :)
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3 years ago
What is the instantaneous velocity of the hummingbird at t=1s?
Liono4ka [1.6K]

The distance - time graph of the humming bird is missing, so i have attached it.

Answer:

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Explanation:

From the attached graph, at time t = 1 s, the corresponding distance is 0.5 m.

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