In an automobile collision, a 44-kilogram passenger moving at 15 meters per second is brought to rest by an air bag during a 0.1
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Answer:
The escape velocity on the planet is approximately 178.976 km/s
Explanation:
The escape velocity for Earth is therefore given as follows
The formula for escape velocity, , for the planet is
Where;
= The escape velocity on the planet
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
m = The mass of the planet = 12 × The mass of Earth,
r = The radius of the planet = 3 × The radius of Earth,
The escape velocity for Earth, , is therefore given as follows;
= 16 ×
Given that the escape velocity for Earth, ≈ 11,186 m/s, we have;
The escape velocity on the planet = ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.