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butalik [34]
3 years ago
15

A squirrel sitting on the ground starts to run with an acceleration of 5.1 m/s 2. How fast is the squirrel going after 0.25 seco

nds?
A. 20.4 m/s
B. 1.28 m/s
C. 0.49 m/s
D. 3.1 m/s
Physics
2 answers:
galben [10]3 years ago
7 0

Answer:

1.28 like she said

Explanation:

thsts what she said

Arisa [49]3 years ago
5 0
Initial speed = 0
final speed = v
acceleration = 5.1 
time taken = 0.25
v=u+at
v=1.28 m /s
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The correct answer is - B. Increase the time it takes to stop the egg once it hits his hand.

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Answer:

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mA/mB = 0.96

Mean radius for A = mA = (8.1 × 10^3)/2 = 4.05 × 10^3 km

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Volume of a sphere = 4/3Πr3

Mean volume for A = (4/3) × Π × (4.05 × 10^3)^3

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Since m/v = d ( where m = mass, v = volume and d = density)

mA = 2.784 × 10^11 km3 × dA ...equation 1

mB= 1.437 × 10^12km3 × dB... equation 2

but mA/mB= 0.96

mA = 0.96 × mB

substitute for mA in equation 1

0.96 × mB = 2.784 × 10^11 x dA equation 3

Substitute for mB in equation 3..

(refer to equation 2)

0.96×1.437×10^12 × dB = 2.784 × 10^11 × dA .....equation 4

divide through by the coefficient of dA

dA = (0.96×1.437×10^12×dB)/(2.784 × 10^11)

divide through by dB

dA/dB = 4.955

therefore, the ratio of dA to dB is 5/1

Therefore, the mean density of A is almost five times that of B

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