A very powerful vacuum cleaner has a hose 2.36 cm in diameter. With no nozzle on the hose (no change to hose area), what is the
1 answer:
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Translation of important question part (Google translation used)
Force of 6N causes a displacement of 0.03m. remove the balance and connect a body 0.5 kg to the end, pull it to move it 0.02 m, release it and see how it oscillates.
(a)Determine the spring constant.
(b)Calculate angular velocity, frequency, and oscillation period
Answer:
(a)K=200 N/m
(b) w= 20 rad/s f=3.2 Hz T=0.3125 s
Explanation:
(a)
From Hooke's law, we deduce that F=kx where F is applied force, k is spring constant and x is extension of the spring. Making k the subject of the formula then k=F/x and substituting F with 6 N and x with 0.03 m then k=6/0.03=200 N/m
(b)
Angular velocity, w is given by where m is the mass and k is spring constant calculated in part a above. Substituting mass with 0.5 kg and k with 200 N/m then
We know that frequency, f is given by and substituting 20 rad/s for w then
Finally, oscillation period, T is usually the reciprocal of frequency hence T=1/f and substituting f with 3.2 Hz then T=1/3.2=0.3125 s
125 W is the power output of this machine.
Answer:
Explanation:
Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.
So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is
As Work done = Force acting on the machine × Displacement
So
Power = =125 W
So, 125 W is the power output of this machine.