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natka813 [3]
3 years ago
10

Andy and Charlie are riding on a merry-go-round. Andy rides on a horse at the outer rim of the circular platform, twice as far f

rom the center of the circular platform as Charlie, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, which of the following best describes Andy's angular speed?'
Physics
1 answer:
Volgvan3 years ago
3 0

Complete Question:

Andy and Charlie are riding on a merry-go-round. Andy rides on a horse at the outer rim of the circular platform, twice as far from the center of the circular platform as Charlie, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, which of the following best describes Andy's angular speed?'

( ) twice Charlie’s

( ) impossible to determine.

( ) the same as Charlie’s

( ) half of Charlie’s

Answer:

The same as Charlie's

Explanation:

As a merry-go-round is a rigid body, all points in the rotating body must have the same angular velocity, i.e., thet must rotate the same angle in the same time.

Otherwise, the distance between any pair of points on a given radius could be different in different times, which is not possible in a rigid body,

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Two charges (q1 = 3.8*10-6C, q2 = 3.2*10-6C) are separated by a distance of d = 3.25 m. Consider q1 to be located at the origin.
Sergio039 [100]

Answer:

The distance is 1.69 m.

Explanation:

Given that,

First charge q_{1}= 3.8\times10^{-6}\ C

Second charge q_{2}=3.2\times10^{-6}\ C

Distance = 3.25 m

We need to calculate the distance

Using formula of electric field

E_{1}=E_{2}

\dfrac{kq_{1}}{x^2}=\dfrac{kq_{2}}{(d-x)^2}

\dfrac{q_{1}}{q_{2}}=\dfrac{(x)^2}{(d-x)^2}

\sqrt{\dfrac{q_{1}}{q_{2}}}=\dfrac{x}{d-x}

x=(d-x)\times\sqrt{\dfrac{q_{1}}{q_{2}}}

Put the value into the formula

x=(3.25-x)\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x+x\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x=\dfrac{3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}}{(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})}

x=1.69\ m

Hence, The distance is 1.69 m.

5 0
3 years ago
A machine shop worker reports the mass of an aluminum cube as 176 g. If one side of the cube measures 4 cm, what is the density
Zarrin [17]

-- Since it's a cube, its length, width, and height are all the same 4 cm .

-- Its volume is (length x width x height) = 64 cm³ .

-- Density = (mass) / (volume)

                = (176 g) / (64 cm³) 

                =         2.75 gm/cm³ .

6 0
3 years ago
a sensor light installed on the edge of a home can detect motion for a distance of 50 feet in front and with a range of motion o
Dvinal [7]

Answer:

4363.3231 feets²

Explanation:

Given that :

Distance, r = 50 ft

θ = 200°

The arc length of area covered :

Arc length = θ/360° * πr²

Arc length = (200/360) * 50 ft ^2 * π

Arc length = 0.5555555 * 2500 * π

Arc length = 4363.3231 feets²

7 0
2 years ago
A straight line means the object travels at ........... speed
Georgia [21]
If it's a distance graph, then it's a constant speed.
5 0
3 years ago
Read 2 more answers
Answer the following in 1-2 complete sentences:
mojhsa [17]

Answer:

The graph with a more steeper slope

Explanation:

If the x axis represented time and the y axis represented speed the steeper the slope the more faster something was moving in a shorter amount of time. On the other hand a less steeper slope means an object is gradually picking up speed in a longer amount of time thus makeing it slower

HOPE THIS HELPED:)

8 0
3 years ago
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