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AlekseyPX
3 years ago
10

Can someone please answer. There is one problem. There is a picture. Thank you!

Mathematics
1 answer:
jonny [76]3 years ago
5 0
SA=4pir^2
78.54km^2=SA
78.54=4pir^2
divide both sides by 4
19.635=pir^2
aprox pi=3.14 so divide both sides by 3.14
6.25318=r^2
sqrt both sides
2.50063=r
round
radius=2.5km

this question is flawed in that it gives the wrong units

answer is the option with 2.5 in it
2nd one
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Determine the value of x.<br><br>A. 4√2<br><br>B. 2/√2<br><br>C. 2√2<br><br>D. 2
ZanzabumX [31]

Answer:

\huge\boxed{\sf C.}

Step-by-step explanation:

sin 45 = opposite / hypotenuse

<u>Where opposite = x , hypotenuse = 4</u>

sin 45 = x / 4

\sf \frac{\sqrt{2} }{2 } = \frac{x}{4} \\\\x = \frac{4\sqrt{2} }{2} \\\\x = 2\sqrt{2} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
3 0
3 years ago
The distribution of lifetimes of a particular brand of car tires has a mean of 51,200 miles and a standard deviation of 8,200 mi
Orlov [11]

Answer:

a) 0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

b) 0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

c) 0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

d) 0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 51200, \sigma = 8200

Probabilities:

A) Between 55,000 and 65,000 miles

This is the pvalue of Z when X = 65000 subtracted by the pvalue of Z when X = 55000. So

X = 65000

Z = \frac{X - \mu}{\sigma}

Z = \frac{65000 - 51200}{8200}

Z = 1.68

Z = 1.68 has a pvalue of 0.954

X = 55000

Z = \frac{X - \mu}{\sigma}

Z = \frac{55000 - 51200}{8200}

Z = 0.46

Z = 0.46 has a pvalue of 0.677

0.954 - 0.677 = 0.277

0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

B) Less than 48,000 miles

This is the pvalue of Z when X = 48000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{48000 - 51200}{8200}

Z = -0.39

Z = -0.39 has a pvalue of 0.348

0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

C) At least 41,000 miles

This is 1 subtracted by the pvalue of Z when X = 41,000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{41000 - 51200}{8200}

Z = -1.24

Z = -1.24 has a pvalue of 0.108

1 - 0.108 = 0.892

0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

D) A lifetime that is within 10,000 miles of the mean

This is the pvalue of Z when X = 51200 + 10000 = 61200 subtracted by the pvalue of Z when X = 51200 - 10000 = 412000. So

X = 61200

Z = \frac{X - \mu}{\sigma}

Z = \frac{61200 - 51200}{8200}

Z = 1.22

Z = 1.22 has a pvalue of 0.889

X = 41200

Z = \frac{X - \mu}{\sigma}

Z = \frac{41200 - 51200}{8200}

Z = -1.22

Z = -1.22 has a pvalue of 0.111

0.889 - 0.111 = 0.778

0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

4 0
3 years ago
3-2i/1+4i include each step necessary in simplifying
Likurg_2 [28]

Answer:

\frac{3-2i}{1+4i}=\frac{11}{17}-\frac{10}{17}i

Step-by-step explanation:

\frac{3-2i}{1+4i} <-- Given

\frac{3-2i}{1+4i}*\frac{1-4i}{1-4i} <-- Multiply by the conjugate of the denominator as a factor of 1

\frac{(3-2i)(1-4i)}{(1+4i)(1-4i)}

\frac{(3)(1)+3(-4i)-2i(1)-2i(4i)}{(1)(1)+1(-4i)+4i(1)+4i(-4i)} <-- Use the Distributive Property and FOIL

\frac{3-12i-2i-8i^2}{1-4i+4i-16i^2}

\frac{3-10i-8i^2}{1-16i^2}

\frac{3-10i-8(-1)}{1-16(-1)} <-- Rewrite i^2 as -1

\frac{3-10i+8}{1+16}

\frac{11-10i}{17}

\frac{11}{17}-\frac{10}{17}i <-- Rewrite in a\pm bi form

8 0
3 years ago
The gazebo in the park is an octagon. Each side of the gazebo is 4 feet long. What is the perimeter of the gazebo?
pychu [463]
The answer is A because an octagon has 8 sides and if each side is 4 feet you would multiply 4 times 8 and get 32.
4 0
3 years ago
Read 2 more answers
Anderson has $50 in his savings account. He deposits $5 every week. His father also deposits $20 into the account every time And
vodomira [7]
50 + 5w + 20m
The constant is 50.
A coefficient is 5 and another is 20.
A variable is w and another is m.
4 0
3 years ago
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