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ella [17]
3 years ago
9

Help with 9 and 10....

Mathematics
2 answers:
maw [93]3 years ago
8 0
Number the answer is 4.5 as the slope and -2 as the y-intercept and number 10 the slope is -1 and the y-intercept is 1
Marta_Voda [28]3 years ago
4 0
First step is to label at the top for the first pair as x1 and y1...then the next pair x2 and y2. ..so what u do is u subtract y2 from y1...and then draw a division line under as if u would divide..and x2 minus x1...and what that answer is for both while still the y answer over top and the x answer under u divide it..once u get the answer u have to put it in a point slope form...which is y-y1 =m(x-x1)..m is slope...u can pick any points which ever is best..and solve..also if u didn't know the y1 gets brought to the other side of the equal sign to go with x1,adding or subtracting depending on the number...it will end up being in slope intercept form of a equation..P.S. if the y1 is a negative compared with the equation it will be positive...ex..y--1=y+1..same goes with x
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Please help quarter ends tomorrow and I don’t know what to do I’m failing all my classes
Nutka1998 [239]

Step-by-step explanation:

x = -10, y = 10

y= -4x+4

m1×m2 = -1

-4 × m2 = -1

m2 = 1/4

y-y1 = m(x-x1)

y-10 = 1/4(x+10)

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(×4)

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3 0
3 years ago
HELP MEEEEEEEEEE......?.?.?(.?:).).).).).).).)
stepladder [879]

Answer:

The answer is C

Step-by-step explanation:

Let X and Y be two proportional quantities and let K be constant.

Y=KX so Y/X=K

So for Equation number 1 we have 4y=3x and we will fill it in for 4/3=K

solving to get 1.33...

Now repeat this for the rest to complete the chart

1-  1.33...

2.  1.6

3-  1.33...

4-  0.625

Now we can see that 1 and 3 are the same, so that's how you get your answer, hope this helps!

8 0
3 years ago
Read 2 more answers
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3 years ago
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Alexus [3.1K]

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8 0
2 years ago
How to solve this question
VMariaS [17]
<span>The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

<span>\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2

Since variance has to be 14, we set \sigma^2  = 14 and solve for m

14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\&#10;14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\&#10;0 = \frac{-88}{9}  -\frac{14}{9}m + \frac{2}{9}m^2&#10;

quadratic formula


m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\&#10;m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \frac{10}{3}  }{\frac{4}{9} } \\&#10;m = 11, -4

-4 doesnt' work as it is not a positive integer

m = 11


</span></span>
5 0
3 years ago
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