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sesenic [268]
3 years ago
15

An ant starts at (0, 0), and only makes moves of length 1 in the positive x directions or the positive y direction. How many pat

hs are there from the ant that end at (3, 3) but never pass through (2, 3)
Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0

Answer:

The number of paths that are there from the ant that end at (3, 3) but never pass through (2, 3) is 4.

Step-by-step explanation:

The possible pathways are as follows:

(0, 0) → (1, 0) → (2, 0) → (3, 0) → (3, 1) → (3, 2) → (3, 3)

(0, 0) → (1, 0) → (2, 0) → (2, 1) → (2, 2) → (3, 2) → (3, 3)

(0, 0) → (1, 0) → (1, 1) → (1, 2) → (2, 2) → (3, 2) → (3, 3)

(0, 0) → (0, 1) → (0, 2) → (1, 2) → (2, 2) → (3, 2) → (3, 3)

Thus, the number of paths that are there from the ant that end at (3, 3) but never pass through (2, 3) is 4.

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In ΔQRS, the measure of ∠S=90°, QR = 82 feet, and RS = 60 feet. Find the measure of ∠R to the nearest tenth of a degree.
dsp73

Answer:

43.0°

Step-by-step explanation:

cos∅=adj/hyp

cos∅=60/82

∅=cos-1 60/82

∅=cos-1  0.731707317073

∅=42.97028393174°

Round: 43.0°

8 0
3 years ago
Read 2 more answers
-9+__ =-3 find the missing value
aalyn [17]

Answer:

6

Step-by-step explanation:

-9+6=-3

5 0
3 years ago
Read 2 more answers
Does 2, 5, and 7 make a right triangle
MakcuM [25]

Answer:  No, we don't have a right triangle

==========================================================

Explanation:

If a triangle with sides a,b,c makes the equation a^2+b^2 = c^2 true, where c is the longest side, then this triangle is a right triangle. This is the converse of the pythagorean theorem.

Here we have a = 2, b = 5 and c = 7.

So...

a^2+b^2 = c^2

2^2+5^2 = 7^2

4+25 = 49

29 = 49

The last equation is false, so the first equation is false for those a,b,c values. Therefore, we do <u>not</u> have a right triangle.

------------

In contrast, consider the classic 3-4-5 right triangle

a = 3, b = 4 and c = 5 would make a^2+b^2 = c^2 true because 3^2+4^2 = 5^2 is a true equation (both sides lead to 25).

6 0
3 years ago
Can someone help pleasere
galben [10]
C=-3. (2c)^3
(2(-3))^3
(2-3)^3
(-1)^3
-1*-1*-1=
-1
4 0
3 years ago
a cylinder has radius 1.6 meters. it’s volume is 95 cubic meters. find it’s height to the nearest tenth of a meter
erastova [34]
H = 11.81 m


v= π r2 h

h = v/ π r2 = 95/ π 1.6(2)* = 11.81228m or just 11.81


*(2) is squared


hope this helped haha
6 0
3 years ago
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