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OleMash [197]
3 years ago
14

A 3,000-N force acts on a 200-kg object, what is the acceleration?​

Physics
2 answers:
Serjik [45]3 years ago
7 0

Answer:

15 m/s

Explanation:

For this problem we have to find the formula for acceleration.

F = ma

So since we already know force and looking for acceleration, we have to change it up a bit.

A = F / m

The force is 3000-N

A = 3000/ m

The mass is 200-kg

A = 3000/ 200

Do the division:

3000/ 200

15

A = 15

Zepler [3.9K]3 years ago
6 0

Answer:

15

Explanation:

a = F/ m

3000 / 200 = 15

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enot [183]

Answer:

60°

Explanation:

Formula

360/n (if the number is an odd number) or

360/n-1 (if the number is even) (to arrive at an odd number)

SO. 5 is an odd number but not a multiple of 360, so we will use 6 an even number.

360/60-1

360/60=6 images

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A very long insulating cylinder of charge of radius 2.60 cm carries a uniform linear density of 15.0 nC/m . Part A If you put on
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Given Information:  

Radius = ra = 2.60 cm = 0.026 m

Density = J = 15.0 nC/m

change in potential difference = ΔV = 200 V

Required Information:  

Distance = d = ?

Answer:

distance = 0.088 m

Explanation:

As we know

ΔV = Vb - Va = J/4πε₀*ln(rb/ra)

Where ra and rb is the point where potential difference is Va and Vb respectively

1/4πε₀ = 9x10⁹ N.m²/C²

We want to find the distance d = rb - ra

ΔV = J/4πε₀*ln(rb/ra)

200 = 9x10⁹*15x10⁻⁹*ln(rb/ra)

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taking e on both sides yields

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4.39 = rb/ra

rb = 4.39*0.026

rb = 0.114 m

Therefore, the required distance is

d = rb - ra

d = 0.114 - 0.026

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Therefore, the other probe must be placed 0.088 m from the surface so that the voltmeter reads 200 V

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T = 256/70 = 3.66 hours = 3 hours and 39.6 minutes

If you leave at 3:00, then at 6 hours and 39.6 minutes, you will get there.

Hope this helps!

:)

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