Answer:
When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.
When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.
Explanation:
 
        
             
        
        
        
Answer:
I DONT KNOW WHAT TO DO SORRY
Explanation:
EVEN ME IM NOT SURW
 
        
             
        
        
        
Answer:
<h2>32m/s^2</h2>
Explanation:
We want to find the acceleration based on the given data
Given
distance s=400m
time t= 5s
u= 0m/s since it started from rest
We apply the following expression
s=ut+1/2at^2
substituting we have
400=0*5+1/2*a(5)^2
400=25a/2
cross multiply 
25a=400*2
25a=800
divide both sides by 25 we have
a=800/25
a=32m/s^2
The acceleration is 32m/s^2