Answer:
2H+ + SO4^2- +2Na+ + 2OH- ------------> 2Na+ + SO4^2- + 2H2O
Explanation:
In writing ionic reaction equations, we omit spectator ions, that is, ions that do not participate actively. Both the reactants and products are broken up into their constituent ions and a balanced equation involving ions only is written. Ionic equation balance usually require good knowledge of the reaction and nature of the reactants The dissolved compounds only are written as ions.
Explanation:
perimeter of circle - 2pieR
- pie D
radius R - 7 cm
perimeter- 2×22/7×7 (7 and 7 got cancalled)
2×22
44 cm
Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
Sugar. (We need a design tech section)
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