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3 years ago

giving the incomplete equation 2N2O5 (g) which set of products completes and balances the incomplete equarion

Chemistry

1 answer:

a_sh-v [17]3 years ago

7 0

Answer:

The complete question is as follows

Given the incomplete equation: 2 N2O5(g) ==> Which set of products completes and balances the incomplete equation?

A)2 N2(g) + 3 H2(g)

B)2 N2(g) + 2 O2(g)

C)4 NO2(g) + O2(g)

D)4 NO(g) + SO2(g)

The correct option is C) 4NO2(g) + O2(g)

Explanation:

Note that the products should be NO2 and O2 since the reactant is entirely made up of N and O. option A is not correct as hydrogen cannot emerge as a product in this reaction. Matter can never be created or be destroyed bu can only change in a chemical reaction. Option D is not also correct for the same reason.

Option B is not correct since it did not balance the number of atoms of O and N in the reactant side of the equation.

The option C) 4NO2(g) + O2(g) is therefore the right option since it balances both the elements and the number of atoms of the elements present.

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What are some similarities between space and earth pollution?

yawa3891 [41]

Both are caused by human ignorance. Both have the ability to kill those in them. Both can become compact to create new material.

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3 years ago

You are working in your laboratory and decide to do some cleaning. You find a test tube with some brown substance congealed at t

Anna [14]

Answer:

The mystery substance is C. Bromine (Br)

Explanation:

Argon (Ar) is a noble gas. Whose freezing point is -189 °C (very low), thus it cannot be the frozen substance. Also, it is not reactive, thus is would have not reacted with iron. Hence, argon is not the mystery substance.

Scandium (Sc) is a metal from group 3 of the periodic table, thus is will not react with iron. Thus, scandium is not the mystery substance.

Both bromine and iodine are halogens (group 17 of the periodic table).

The freezing point of bromine is −7.2 °C, and the freezing point of iodine is 113.7 °C. Thus, both could be solids (frozen) in the lab.

The reactivity of the halogens decrease from top to bottom inside the group. Bromine is above iodine. Then bromine is more reactive than iodine.

Bromine is reactive enough to react with iron. Iodine is not reactive enough to react with iron.

You can find in the internet that bromine vapour over hot iron reacts producing iron(III) bromide. Also, that bromine vapors are red-brown.

Therefore, the mystery substance is bromine (Br).

7 0

3 years ago

If I go a distance of 5 meters in 30 seconds, what is my speed

Tresset [83]

Answer:

0.166 m/s

Explanation:

speed = distance / time

= 5 / 30

= 0.166 m/s

6 0

2 years ago

flammable liquid is being pumped out of a drum into a bucket using a hand pump. describe an appropriate grounding and bonding pr

lutik1710 [3]

When transferring flammable liquids from storage drums to smaller electrically conductive containers, bonding and grounding are required. In any workplace, you should do the same whenever you move these liquids between conductive containers.

<h3>What exactly occurs in this case?</h3>

Ground dispensing drums in the area for storing and dispensing flammable liquids. Connecting the container to an already grounded, electrically conductive object grounds it. This could be a grounded metal construction framework, a buried metal plate, a metallic subsurface gas piping system, or metal water pipes. Sparks are prevented from discharging by bonding the two containers together and grounding one of them. All connections for bonding and grounding must be made from bare metal to bare metal.

To know more about Flammable liquids, visit-brainly.com/question/3702349

#SPJ4

3 0

11 months ago

The combustion of methane is a reaction commonly used in chemistry problems due to its ability to fit into multiple topics. So i

lyudmila [28]

Answer:

20.76 L OF CO2 WILL BE PRODUCED BY 45 G OF METHANE.

Explanation:

Equation of the reaction:

CH4 + 02 --------> CO2 + 2H20

Molar mass of methane = ( 12+ 1*4) g/mol = 16 g/mol

Calculate the number of moles present in 45 g of methane

1 mole of methane = 16 g / mol of methane

(45 / 16) mole of methane = 45 g of methane

= 2.8125 moles

Using the ideal gas equation:

PV = nRT

P = 1 atm

n = 2.812 moles

T = 90 C

R = 0.082 L atm/ mol C

V = unknown

So we have:

V = nRT / P

V = 2.8125 * 0.082 * 90 / 1

V = 20.756 L

In the production of CO2 by 45 g of methane, 20.756 L of methane was used.

Then, the volume of CO2 produced by this volume will be 20.756 L since 1 mole of methane produces 1 mole of CO2.

In other words;

1 mole of CH4 = 1 mole of CO2

22.4 dm3 of CH4 = 22.4 dm3 of CO2

20.76 DM3 = 20.76 dm3

The volume of CO2 produced will therefore be 20.76 L

8 0

2 years ago